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Nezavi [6.7K]
2 years ago
6

Which equation has the same solution as x^2+10x+9 = 4

Mathematics
1 answer:
tresset_1 [31]2 years ago
8 0
To factor you must play with factors which multiply to
9

(
1
×
9
,

3
×
3
,

9
×
1
)
(
x
−
9
)
(
x
−
1
)
=
0
Now, solve each factor for
0
:
x
−
9
=
0
x
−
9
+
9
=
0
+
9
x
−
0
=
9
x
=
9
and
x
−
1
=
0
x
−
1
+
1
=
0
+
1
x
−
0
=
1
x
=
1
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Step-by-step explanation:

5 0
2 years ago
3. Find two possible lengths for CD if C, D, and E
Kaylis [27]

Given :

C, D, and E  are col-linear, CE = 15.8 centimetres, and DE=  3.5 centimetres.

To Find :

Two possible lengths for CD.

Solution :

Their are two cases :

1)

When D is in between C and E .

.                   .           .

C                  D          E

Here, CD = CE - DE

CD = 15.8 - 3.5 cm

CD = 12.3 cm

2)

When E is in between D and C.

.       .                .

D      E              C

Here, CD = CE + DE

CD = 15.8 + 3.5 cm

CD = 19.3 cm

Hence, this is the required solution.

3 0
3 years ago
Ashley spend half of her weekly allowance playing mini golf .to earn more money her parents let her wash the car for $9. what is
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Her weekly allowance is $8.
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3 years ago
Please answer There is a bag filled with 3 blue and 5 red marbles. A marble is taken at random from the bag, the colour is noted
Misha Larkins [42]

Answer:

\frac{15}{28}  is the required probability.

Step-by-step explanation:

Total number of Marbles = Blue + Red = 3 + 5 = 8

Probability of getting blue = \frac{3}{8}

Probability of not getting a blue =\frac{5}{8}

To get exactly one blue in two draws, we either get a blue, not blue, or a not blue, blue.

<u>First Draw Blue, Second Draw Not Blue:</u>

1st Draw: P(Blue) = \frac{3}{8}

2nd Draw: P(Not\:Blue)=\frac{5}{7}  (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

P(Event)=\frac{3}{8}\cdot \frac{5}{7}=\frac{15}{56}

<u>First Draw Not Blue, Second Draw Not Blue:</u>

1st Draw: P(Not\:Blue)=\frac{5}{8}

2nd Draw: P(Not\:Blue)=\frac{3}{7}  (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

P(Event)=\frac{5}{8}\cdot \frac{3}{7}=\frac{15}{56}

To get the probability of exactly one blue, we add both of the events:

\frac{15}{56}+\frac{15}{56}=\frac{15}{28}

4 0
3 years ago
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