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olchik [2.2K]
3 years ago
11

John had 80 filers to post around town. Last week, he posted 1/4 of them. This week, he posted 3/5 of the remaining filers. How

many filers has he still not posted?
Mathematics
2 answers:
Reil [10]3 years ago
4 0

Answer: 24 fliers

Step-by-step explanation:

he had 80 to begin with so last week if he posted 1/4 of them he would have 3/4 left and

3/4 * 80 = 60

and then if he posts 3/5 of the 60 remaining fliers he would have 2/5 left over and

2/5 * 60 = 24

so your answer is 24 fliers

aniked [119]3 years ago
3 0

Answer:

24 fillers

Step-by-step explanation:

he had 80 to begin with so last week if he posted 1/4 of them he would have 3/4 left and

3/4 * 80 = 60

and then if he post 3/5 of the 60 remaining filers he would have 2/5 left

2/5 * 60 = 24

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Leya [2.2K]

Answer: 1859.5 mini bears

Step-by-step explanation:

From the information given in the question,

10 mini bars = 12.1 grams

10 regular bars = 23.1 gram

1 super bear = 2250 grams

To eat enough mini bears to match the super bears, the number that it'll take will be:

Since 10 mini bars = 12.1 grams

1 mini bear = 12.1 grams / 10 = 1.21 gram

Since 1 super bear = 2250 grams, the number of mini bears needed to equate this will be:

= 2250/1.21

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14,880 seconds i think
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Answers and Step-by-step explanations:

1. We need to plug in values of x into the functions f(x) and g(x):

f(2) = 2.5 * 2 - 10.5 = -5.5                         g(2) = 64 * (0.5^2) = 16

f(3) = 2.5 * 3 - 10.5 = -3                            g(3) = 64 * (0.5^3) = 8

f(4) = 2.5 * 4 - 10.5 = -0.5                         g(4) = 64 * (0.5^4) = 4

f(5) = 2.5 * 5 - 10.5 = 2                             g(5) = 64 * (0.5^5) = 2

f(6) = 2.5 * 6 - 10.5 = 4.5                          g(6) = 64 * (0.5^6) = 1

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(a) Notice that at 14 on the x-axis, the blue line is above 4. Meanwhile, at 14, the red line is less than 2. Obviously, we can see that if the printed ad revenue was less than 2 and the online ad revenue was greater than 4, that's more than a double, so the lead marketing executive is correct.

(b) The approximate year that the revenues were equal is the place where the lines intersect. It's approximately at Year 7.5.

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(a) The Western Beach is clearly decreasing; it is decreasing by 2 ft per year. Meanwhile, the Dunes Beach is clearly increasing; it's increasing by 5 ft per year. (I'm not sure what kinds of "patterns" you're looking for).

(b) Year 11 and 12; this is because here, Western is going from 78 to 76 ft and Dunes is going from 75 to 80, so they'll likely coincide sometime in that time interval.

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Then the plane that passes through the origin with this as its normal vector has equation

⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

We want the plane to pass through the point (9, 6, 0), so we just translate every vector pointing to the plane itself by adding ⟨9, 6, 0⟩,

(⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ - ⟨9, 6, 0⟩) • ⟨7, -7, -6⟩ = 0

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⟨<em>x</em> - 9, <em>y</em> - 6, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

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