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lana66690 [7]
3 years ago
14

I need major help on this question try your best

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0
First find sq 17 and sq 12
sq 17 = 4.123
sq 12 = 3.464
Now you can list them from greatest to least
5.03709...
4.923935
sq 17
sq 12
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What is the area of triangle ABC? Round to the nearest hundredth of a square unit. 17. 75 square units 81. 33 square units 372.
jolli1 [7]

The area of the triangle ABC is 81. 33 square units.

We have to determine

What is the area of triangle ABC?

<h3>What is the formula for the area of a triangle?</h3>

The area of the triangle is determined by;

\rm Area \ of \ triangle = s\sqrt{s(s-a)(s-b)(s-c)}

Where the value of s is = a + b + c= 12 + 14 + 16 = 42

Substitute all the values in the formula;

\rm Area \ of \ triangle = \sqrt{s(s-a)(s-b)(s-c)}\\\\\rm Area \ of \ triangle = \sqrt{21(21-12)(21-14)(21-16)}\\\\\rm Area \ of \ triangle = \sqrt{(21 \times 9 \times 7 \times 5)}\\\\Area \ of \ triangle =\sqrt{6,615}\\\\Area \ of \ triangle = 81.33

Hence, the area of the triangle ABC is 81. 33 square units.

To know more about the Area of the triangle click the link given below.

brainly.com/question/9299277

5 0
2 years ago
In the figure shown above, all the corners form right angles. What is the area of the figure in square units?
asambeis [7]

9514 1404 393

Answer:

  70 square units

Step-by-step explanation:

The overall outline is 15 units wide and 8 units high, for an area of ...

  A = WH

  A = (15 units)(8 units) = 120 units²

__

The white space taken out of that overall area is 5 units high and 15-4-1 = 10 units wide. The area of the white space is ...

  A = (5 units)(10 units) = 50 units²

__

The shaded area is the difference between the overall area and the white space taken out:

  shaded = 120 units² -50 units² = 70 units²

5 0
3 years ago
Li is running a race around the school track he runs 0.327 kilometer during the first half of the race.What is the distance that
Nady [450]
Its far real far I tell you what
5 0
4 years ago
Verify the identity secx-secx sin^2x=cosx
MrMuchimi
Hello :
   *  secx = 1/cosx
 cos²x+sin²x= 1
**sin²x = 1-cos²x
by (*) : 
secx-secx sin²x=(1/cosx) -(1/cosx) sin²x
                        = (1/cosx)(1-  sin²x)....factory :(1/cosx)
by(**)
                      secx-secx sin²x  =  (1/cosx)cos²x
                      secx-secx sin²x  = cosx ...( simplify by : cosx)
6 0
3 years ago
Ther ratio of the number of adults to the number of students at the prom has to be 1:10. last year there were 477 more students
Alika [10]

Answer:

53 adults

Step-by-step explanation:

Let

x---------> the number of adults

y -------> the number of students

we know that

\frac{x}{y} =\frac{1}{10}

y=10x -----> equation A

y=x+477 -----> equation B

Equate equation A and equation B

10x=x+477

solve for x

10x-x=477

9x=477

x=53

therefore

There are 53 adults

6 0
3 years ago
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