A = 1/2(b1+b2) h
A = 1/2(6 + 12) 8
A = 9 * 8
A = 72
answer
A = 72 ft^2
To find distance between points C(xC,yC) and <span>B(xB,yB)</span>, we use formula:
d(C,B)=√[(xB−xC)^2+(yB−yC)^2]
d(C,B)=√[(16-10)^2+(12−4)^2]
d(C,B)=√[6^2+8^2]
d(C,B)=√(36+64)
d(C,B)=√100
d(C,B)=10 ft
<span>The length of fencing required</span> = 6 + 12 + 8 + 10 = 36 ft
