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zheka24 [161]
3 years ago
9

One seal weights 22 pounds.Another seal weighs three thins. As much how much do the seals weigh altogether

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
3 0

Answer:

88 lbs

Step-by-step explanation:

22+22(3)=88

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Write the slope-intercept form of the equation of each line given the slope and y-intercept
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The slope-intercept form of the equation for a line is ...
  y = (Slope)x + (y-intercept)

Put the given information in the appropriate spot in the equation. Simplify as required.
  y = (-1/3)x + 0
can be simplified to

y = (-1/3)x
6 0
2 years ago
Before leaving to visit Mexico, Levant traded 270 American dollars and received 3,000 Mexican pesos. When he returned from Mexic
Shtirlitz [24]

The question is incomplete:

Before leaving to visit Mexico, Levant traded 270 American dollars and received 3,000 Mexican pesos. When he returned from Mexico, he had 100 pesos left.

How much will he receive when he exchanges these pesos for dollars?

Answer:

9 dollars

Step-by-step explanation:

To find the amount that Levant will receive when he exchanges these pesos for dollars, you can use a rule of three using the information provided:

270 dollars   →  3,000 Mexican pesos

        x           ←  100 Mexican pesos

x=(270*100)/3,000=9 dollars

According to this, the answer is that he will receive 9 dollars.

4 0
2 years ago
Determine
mihalych1998 [28]

Answer:

=4.+2.

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector \vec b is a linear combination of \vec a_1 and \vec a_2 if there are two scalars x_1, x_2 such as

\vec b=x_1\vec a_1+x_2\vec a_2

In our case, all the vectors are given in R^3 but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

\vec a_1=,\ \vec a2=,\ \vec b=

We set the equation

=x_1.+x_2.

Multiplying both scalars by the vectors

=+

Equating each coordinate, we get

4x_1-4x_2=8

5x_1+3x_2=26

-4x_1+3x_2=-10

Adding the first and the third equations:

-x_2=-2

x_2=2

Replacing in the first equation

4x_1-4(2)=8

4x_1=8+8

x_1=4

We must test if those values make the second equation become an identity

5(4)+3(2)=20+6=26

The second equation complies with the values of x_1 and x_2, so the solution is

=4.+2.

8 0
3 years ago
Classifying quadrilaterals
zmey [24]

Answer:

A quadrilateral is a polygon with four sides.

Practicly anything with 4 sides like square, Rectangle ,and rhombas

Im sorry if i didn't answer your question but i did not get what you were saying but here is an image that can maybe help you

7 0
3 years ago
Ana walked 13/3 miles write 13/3 as a mixed numder
-BARSIC- [3]
Divide 13 by 3. 
If there is a remainder, keep that as fraction. 
.
4 1/3
12/3=4 
4= whole number
13-12=1
1/3
4 + 1/3 = 4 1/3 
Your answer is 4 1/3
8 0
2 years ago
Read 2 more answers
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