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kotykmax [81]
3 years ago
7

In a field of ducks and a dog someone counted 25 heads and 80 legs. How many dogs and ducks are there

Mathematics
2 answers:
Anni [7]3 years ago
8 0
Ducks have two legs while dogs have four legs and their are 25 heads, so there must be 15 dogs and 10 ducks.
15(heads) x 4(legs/head) = 60 legs      10 (heads) x 2 (legs/head) = 20 legs
                                      60 legs + 20 legs = 80 legs
                                      15 heads + 10 heads = 25 heads
(legs/head) is read as legs per head
brilliants [131]3 years ago
6 0
Ducks have 1 head. Dogs have 1 head.
Ducks have 2 feet. Dogs have 4 feet.

If x = no. of ducks and g = no. of dogs

x + g = 25
2x + 4g = 80

Let's use substitution to solve.

x + g = 25 ⇒ x = 25 - g
replace x with 25 - g in the other equation and solve for g

2x + 4g = 80
2(25 - g) + 4g = 80
50 - 2g  + 4g = 80
50 + 2g = 80
2g = 30
g = 15

Now use g = 15 in an earlier equation to find x.

x + g = 25
x + 15 = 25
x = 10
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24,840 cubic inches

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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7 0
2 years ago
Simplify: -(16 - 5x) 5×-16/ 5× + 16 / -5×-16/ -5 + 16​
bulgar [2K]

Answer:

(16 (1280 x - 4071))/25

Step-by-step explanation:

Simplify the following:

16 - (-16 (-16)×5×16 (16 - 5 x))/(5 (-5) (-5))

Hint: | Express 16/(-5)×(-16)/(-5) as a single fraction.

16/(-5)×(-16)/(-5) = (16 (-16))/(-5 (-5)):

-(-16×5×(-16×16)/(-5 (-5)) (16 - 5 x))/5 + 16

Hint: | Express 5×(-16)/5×(16 (-16))/(-5 (-5)) as a single fraction.

5×(-16)/5×(16 (-16))/(-5 (-5)) = (16 (-16) 5 (-16))/(-5 (-5) 5):

16 - (-16 (-16) 16×5)/(-5 (-5) 5) (16 - 5 x)

Hint: | Multiply 16 and -16 together.

16 (-16) = -256:

-(-16-256×5 (16 - 5 x))/(-5 (-5) 5) + 16

Hint: | Multiply -256 and 5 together.

-256×5 = -1280:

-(-16-1280 (16 - 5 x))/(-5 (-5) 5) + 16

Hint: | Multiply -1280 and -16 together.

-1280 (-16) = 20480:

16 - (20480 (16 - 5 x))/(-5 (-5) 5)

Hint: | In 20480/(-5 (-5) 5), divide 20480 in the numerator by 5 in the denominator.

5 | | 4 | 0 | 9 | 6

| 2 | 0 | 4 | 8 | 0

- | 2 | 0 | | |  

| | | 4 | |  

| | - | 0 | |  

| | | 4 | 8 |  

| | - | 4 | 5 |  

| | | | 3 | 0

| | | - | 3 | 0

| | | | | 0:

16 - (4096 (16 - 5 x))/(-5 (-5))

Hint: | Multiply -5 and -5 together.

-5 (-5) = 25:

16 - (4096 (16 - 5 x))/25

Hint: | Put the fractions in 16 - ((16 - 5 x)×4096)/25 over a common denominator.

Put each term in 16 - ((16 - 5 x)×4096)/25 over the common denominator 25: 16 - ((16 - 5 x)×4096)/25 = 400/25 - (4096 (16 - 5 x))/25:

400/25 - (4096 (16 - 5 x))/25

Hint: | Combine 400/25 - (4096 (16 - 5 x))/25 into a single fraction.

400/25 - (4096 (16 - 5 x))/25 = (400 - 4096 (16 - 5 x))/25:

(400 - 4096 (16 - 5 x))/25

Hint: | Distribute -4096 over 16 - 5 x.

-4096 (16 - 5 x) = 20480 x - 65536:

(20480 x - 65536 + 400)/25

Hint: | Group like terms in 20480 x - 65536 + 400.

Grouping like terms, 20480 x - 65536 + 400 = 20480 x + (400 - 65536):

(20480 x + (400 - 65536))/25

Hint: | Evaluate 400 - 65536.

400 - 65536 = -65136:

(20480 x + -65136)/25

Hint: | Factor out the greatest common divisor of the coefficients of 20480 x - 65136.

Factor 16 out of 20480 x - 65136:

Answer: (16 (1280 x - 4071))/25

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The clock was exactly on time at 7am at 1pm the clock was 228 seconds late at that rate how slow was the clock half an hour
yan [13]

Answer:

19 seconds.

Step-by-step explanation:

Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:

1 PM = 13:00

13 - 7 = 6

228/6 = 38

38/2 = 19

Thus, every half hour the clock is delayed 19 seconds.

4 0
2 years ago
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