Here is the compound interest formula solved for years: <span>Years = {log(total) -log(Principal)} ÷ log(1 + rate) </span>Years = {log(800) - log(600)} <span>÷ log(1.025) </span><span>Years = {2.903089987 -2.7781512504} / 0.010723865392 </span>Years = {
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<span>
0.1249387366
} / </span></span></span><span><span><span>0.010723865392 </span>
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</span>
Years =
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<span>
11.6505319708
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That's how many years it takes for the $600 to become exactly $800.00 The question specifically asks how long for the money to be MORE than $800.00?
So, if we enter 800.01 into the equation, then the answer is Years = {log(800.01) - log(600)} <span>÷ log(1.025) </span><span>Years = {2.9030954156 -2.7781512504} / 0.010723865392 </span>Years =
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<span>
0.1249441652
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</span>
</span>
/ 0.010723865392 <span>
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<span>
Years = 11.6510381875
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<span><span> </span></span>
to find out how much pizza is needed, multiply 4/7 by 18 to get 72/7. round up to get 77/7 or 11 pizzas. 77/7 - 72/7= 5/7 so there will be 5/7 left over
The domain of the function that will be derived from the given situation should be restricted to include only the positive integers. This is because we can count the 1/2 or 2/3 or any fraction of a person. Further, there are also no negative number of persons.
