A table is 3 feet and 2 inches wide, and a chair is 25 inches wide. How much wider is the table than the chair?

2 answers:

8 0

- There are twelve inches in a foot.

- Improper fraction way : 3x12=36, 36+2=38, 38-25=13.

- The table is thirteen inches wider than the chair.

- Mixed number way : 3 feet 2 inches. 25/12=2 R=1, 2 feet 1 inch. 3f-2f=1f, 2i-1i=1i

- The table is one foot one inch wider than the chair.

Lostsunrise [7]3 years ago

6 0

A table is 3 feet and 2 inches wide
= 3(12) + 2 = 38 inches wide

a chair is 25 inches wide

38 - 25 = 13 inches

answer: table is 13 inches wider than the chair

You might be interested in

4x^2-7x=15 Solve by factoring and please please please explain or show the work

vodomira [7]

Answer:

x=3 and x=-1.25

Step-by-step explanation:

4x^2-7x=15

subtract 15 from each side:

4x^2-7x-15=0

factor (trying different numbers that the sum is 7 and the quotient is 15)

(2x-6 )(2x+2.5 )=0

2x-6=0 add 6 to each side

2x=6

x=3

2x+2.5=0 subtract 2.5 from each side

2x=-2.5

x=-1.25

8 0

2 years ago

3. (6 Points). Solve the initial value problem y'-y.cosx=0, y(pi/2)=2e

Stells [14]

Answer:

$y=2e^{sin(x)}$

Step-by-step explanation:

Given equation can be re written as

$\frac{\mathrm{d} y}{\mathrm{d} x}-ycos(x)=0\\\frac{\mathrm{d} y}{\mathrm{d} x}=ycos(x)\\\\=> \frac{dy}{y}=cox(x)dx\\\\Integrating \\ \int \frac{dy}{y}=\int cos(x)dx \\\\ln(y)=sin(x)+c$ ............(i)