Use cos^-1(0.6157) and u might find the answer
Answer:
i think B.
Step-by-step explanation:
Hope this helps :p
Answer:
164
The 982 part seems wrong. Are you sure it isn't 981?
around 436 if I use 981 instead. 982 would give a decimal and that would be kinda weird for a part human.
Step-by-step explanation:
You can divide the 205 by 5 to simplify the ratio down. 205/5 = 41. Then you can multiply by 4 to find then number of boys.
981
So you can add the 5 and 4 together to 9 and then divide 981 by 9 to get 109. Then you can multiply by 4 to get 436.
Hope this helps!
Answer:
Three-fifths
Step-by-step explanation:
The number of sections is 5 and the unshaded section is 3 even numbers are 1, 3 and 5. Since 3 is in both cases there are 3 numbers: 1, 3 and 5. So it is three-fifths
Answer: 0.1357
Step-by-step explanation:
Given : Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 
and a mean life span of 
hours.
Here , 
Let x represents the life span of a monitor.
Then , the probability that the life span of the monitor will be more than 14,650 hours will be :-
![P(x>14650)=P(\dfrac{x-\mu}{\sigma}>\dfrac{14650-13000}{1500})\\\\=P(z>1.1)=1-P(z\leq1.1)\ \ [\because\ P(Z>z)=1-P(Z\leq z)]\\\\=1-0.8643339=0.1356661\approx0.1357](https://tex.z-dn.net/?f=P%28x%3E14650%29%3DP%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B14650-13000%7D%7B1500%7D%29%5C%5C%5C%5C%3DP%28z%3E1.1%29%3D1-P%28z%5Cleq1.1%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.8643339%3D0.1356661%5Capprox0.1357)
Hence, the probability that the life span of the monitor will be more than 14,650 hours = 0.1357
