Step-by-step explanation:
3(p2q + pq2 - pq) - 6pq + 3pq2 =
3[-20 × 2 + (-20) × 2 - (-20)] - 6 × (-20) + 3 × 2 × (-20) =
3[-40 + (-40) + 20] - 6 × (-20) + 3 × 2 × (-20) =
3(-40 - 40 + 20) - 6 × (-20) + 3 × 2 × (-20) =
3(-80 + 20) - 6 × (-20) + 3 × 2 × (-20) =
3 × (-60) - 6 × (-20) + 3 × 2 × (-20) =
-180 + 120 + 6 × (-20) =
-180 + 120 + (-120) =
-180 + 120 - 120 =
-60 - 120 = -180
The smallest possible product of these four numbers is 59.0625
<h3>How to find the smallest possible product of these four numbers?</h3>
The equation is given as:
a + b + c + d = 12
The numbers are consecutive numbers.
So, we have:
a + a + 1 + a + 2 + a + 3 = 12
Evaluate the like terms
4a = 6
Divide by 4
a = 1.5
The smallest possible product of these four numbers is represented as:
Product = a * (a + 1) * (a + 2) * (a + 3)
This gives
Product = 1.5 * (1.5 + 1) * (1.5 + 2) * (1.5 + 3)
Evaluate
Product = 59.0625
Hence, the smallest possible product of these four numbers is 59.0625
Read more about consecutive numbers at:
brainly.com/question/10853762
#SPJ1
X = m x 2. X representing amount of movies m being how many months.
Answer is 8 hope this helps
