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vladimir2022 [97]

3 years ago

5

Write the formula for the area of a triangle, A, where b is the base and h is the height of the triangle. Don’t include parenthe

ses in your answer

1 answer:

stich3 [128]3 years ago

4 0

Area= (1/2 b) * h needs l=to hit character limit

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A bag contains 3 red marbles, 5 green marbles and 7 blue marbles. If Janelle picks one marble out of the bag, what is the probab

lisabon 2012 [21]

3+5+7 = 15 total marbles

3 are red

so she has a 3/15 reduces to 1/5 probability of picking a red one

8 0

3 years ago

2x + 3x + 4 equals .

RUDIKE [14]

Add like terms
only add x's together
2x+3x=5x

we can't add x's and numbres so
answer is 5x+4

7 0

3 years ago

There are 24 boys and 16 girls in a hall, each holding coins in their hand.

Dmitry_Shevchenko [17]

Answer:

27

Step-by-step explanation:

total=average ×no.

18×40=720 the no. of coins for all children

12×24=288 no. of coins for boys

720-288=432 for all girls

one girl, mean,divide 432 by 16= 27

5 0

3 years ago

(x+1)^2 (x-4)(-2x+3)<br><br> degree?<br> Ld. Coef?<br> y-int?

8_murik_8 [283]

(x + 1)²(x - 4)(-2x + 3)
(x + 1)(x + 1)(x - 4)(-2x + 3)
(x² + x + x + 1)(-8x² + 3x + 8x - 12)
(x² + 2x + 1)(-8x² + 11x - 12)
(-8x^4 + 11x³ - 12x² - 16x³ + 11x² - 12x - 8x² + 11x - 12)
(8x^4 + 11x³ - 16x³ - 12x² + 11x² - 8x² - 12x - 11x - 12)
8x^4 - 5x³ + 15x² - 23x - 12

6 0

3 years ago

The velocity of an automobile starting from rest is given by the equation below, where v is measured in feet per second and t is

podryga [215]

Answer:

(a) $0.408m/sec^2$

(b) $0.134m/sec^2$

(c) $0.039m/sec^2$

Step-by-step explanation:

We have given velocity as function of t $v(t)=\frac{85t}{(8t+14)}$

Acceleration is equation rate if change of velocity with respect to time

So $a=\frac{dv}{dt}=\frac{(8t+14)85-85t\times 8}{(8t+14)^2}$

(a) Acceleration at t = 5 sec

$a=\frac{(8\times 5+14)85-85\times 5\times 8}{(8\times 5+14)^2}=0.408m/sec^2$

(b) Acceleration at t = 10 sec

$a=\frac{(8\times 10+14)85-85\times 10\times 8}{(8\times 10+14)^2}=0.134m/sec^2$

(c) Acceleration at t = 20 sec

$a=\frac{(8\times 20+14)85-85\times 20\times 8}{(8\times 20+14)^2}=0.039m/sec^2$

5 0

3 years ago