For this case we have by definition, that the total surface area of a regular pyramid with a square base is given by:
Where:
p: It is the perimeter of the base
S: It's the inclination
It is the area of the base
Substituting:
ANswer:
Option B
5^2 +12^2= diagonal^2
25+144=d^2
169= d^2
D= 13
Answer:
f(-2) = 0
f(1) = 12
f(2) = 5
Step-by-step explanation:
f(-2) will lie in the function 
f(1) will lie in the function 
f(2) will lie in the function 
Complete the square:
F(x) = -3x² - 6x - 5
F(x) = -3 (x² + 2x) - 5
F(x) = -3 (x² + 2x + 1 - 1) - 5
F(x) = -3 ((x + 1)² - 1) - 5
F(x) = -3 (x + 1)² + 3 - 5
F(x) = -3 (x + 1)² - 2
The y-intercept has x-coordinate equal to 0, so it corresponds to the value of F(0) :
F(0) = -3 (0 + 1)² - 2 = -3 - 2 = -5
The axis of symmetry is the vertical line running through the vertex of this parabola, so we'll come back to this.
The vertex of the parabola is (-1, -2). This represents the maximum value of F(x), which follows from
(x + 1)² ≥ 0 ⇒ -3 (x + 1)² ≤ 0 ⇒ -3 (x + 1)² - 2 ≤ -2
This is to say, every point on the parabola has a y-coordinate no greater than -2.
As mentioned earlier, the axis of symmetry is the vertical line through the vertex, and its equation is determined by the x-coordinate of the vertex. Hence the AoS is the line x = -1.
