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3 years ago

I need heLP PLS AND THXS

Mathematics

2 answers:

Furkat [3]3 years ago

8 0

Answer:

SAS

Step-by-step explanation:

Airida [17]3 years ago

8 0

Answer:

SAS (side-angle-side)

Step-by-step explanation:

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HELPPP ME PLEASE IVE BEEN 2 hours IN THIS QUESTIONN

Harlamova29_29 [7]

9514 1404 393

Answer:

12.9 square yards

Step-by-step explanation:

The base is an equilateral triangle, so we can assume that the three faces have the same dimensions. Each of those face triangles has an area of ...

A = 1/2bh

A = 1/2(3 yd)(2 yd) = 3 yd²

The base area is computed using the same formula and the given height:

A = 1/2(3 yd)(2.6 yd) = 3.9 yd²

Then the total surface area is that of the base and the three faces:

SA = (3.9 yd²) + 3(3 yd²) = 12.9 yd² . . . total surface area

5 0

2 years ago

Direction: Arrange the following numbers in decreasing order. Write your answer on the blank provided below each number.

rjkz [21]

Answer:

1. 100 000, 89 000, 67 000, 55 000

2. 45 678, 34 567, 23 456, 12 345

3. 98 765, 87 654, 76 543, 65 432-

7 0

3 years ago

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

6 0

3 years ago

Barry read for 15 more minutes than Robert.

Greeley [361]

Hi!

C. v + 15

Barry read for 15 MORE minutes than Robert.

6 0

3 years ago

What is the value of 3 1/2 - 9 3/4

soldi70 [24.7K]

The value or outcome would be -6.25 .

8 0

2 years ago

Read 2 more answers