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patriot [66]
3 years ago
14

I need heLP PLS AND THXS

Mathematics
2 answers:
Furkat [3]3 years ago
8 0

Answer:

SAS

Step-by-step explanation:

Airida [17]3 years ago
8 0

Answer:

SAS (side-angle-side)

Step-by-step explanation:

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Help please it for a really important test
Arada [10]

Answer:

cant tell you the answer but i can tell you the person that messed up isn't that good at math

Step-by-step explanation:

4 0
3 years ago
Which equation best represents this situation?
Harlamova29_29 [7]
Hello!

We have the difference between 30 and x(our unknown value) is equal to 17; so we just simply set it up that way. Always think of x or any variable(like in your question they use p, it can be anything u want, it’s simply a representation of an unknown value we are trying to find)as your unknown and what operation they are implying as in this case it’s subtraction as they want the difference between 30 and x.

So the answer is a. 30-p=17

Hope this helped and any questions please just ask. Thank you!
7 0
3 years ago
Please help me! WILL MARK BRAINLIEST
AURORKA [14]

Answer:

r=45,041

Step-by-step explanation:

455=(94)(22)^2/r

455=(94)(484)/r

455=45,496/r

455r=45,496

r=45,041

7 0
3 years ago
Read 2 more answers
The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
3 years ago
What is wrong with these statements? Correct each one.
aivan3 [116]

2^3 x 2^5

8 x 32

256

2^3 x 2^5 = 256

4 0
3 years ago
Read 2 more answers
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