<span>Which set of line segments could create a right triangle? a 15, 30, 35 b 15, 36, 39 c 15, 20, 29 d 5, 15, 30 = </span>b 15, 36, 39
Answer:
5abc^2/35a^3c^3
Step-by-step explanation:
To bring the fraction: b/7a^2c to a denominator of 35a^3c^3, find the dividend when the 35a^3c^3 is divided by 7a^2c
=35a^3c^3/ 7a^2c
Recall that
a^x/a^y = a^x-y
Hence
35a^3c^3/ 7a^2c = 5a^3-2c^3-1
= 5ac^2
Now multiply the numerator and denominator by the result
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2)
Recall that
a^x * a^y = a^x+y
Hence
b/7a^2c = (b * 5ac^2)/(7a^2c * 5ac^2) = 5abc^2/35a^3c^3
