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Aloiza [94]
3 years ago
8

The graph shows the approximate median annual earings for five occupations. About how much less does a cook earn than a teller?

Annual Earnings $100,000 $90,000 $80,000 $70,000 $60,000 $50,000 $40,000 $30,000 $20,000 $10,000 $0 Cook Teller Professor Actuary Accountant
PLs help​

Mathematics
2 answers:
yan [13]3 years ago
7 0
The cook makes 20,000 a year and the teller makes 25,000 so the answer would be the cook makes 5,000 less than the teller.
UkoKoshka [18]3 years ago
4 0
Professor is the median which is 70,000
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Today joelle walked at a rate of 3 miles per hour and she ran 15 minutes at a rate of 6 miles per hour.How many total miles did
svetoff [14.1K]
I added a screenshot with the complete question

<u><em>Answer:</em></u>
Total miles = 2.5 miles

<u><em>Explanation:</em></u>
<u>1- While walking:</u>
We are given that Joelle walked 20 minutes at a rate of 3 miles per hour.
This means that she walked \frac{20}{60} =  \frac{1}{3} of an hour at a rate of 3 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
<u>Substitute with the givens to get the distance she covered while walking:</u>
Distance = 3 * \frac{1}{3} = 1 mile

<u>2- While running:</u>
We are given that Joelle ran 15 minutes at a rate of 6 miles per hour
This means that she ran \frac{15}{60} =  \frac{1}{4} of an hour at a rate of 6 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
<u>Substitute with the givens to get the distance she covered while running:</u>
Distance = 6 * \frac{1}{4} = 1.5 miles

<u>3- getting the total mileage:</u>
Total distance she covered = distance while walking + distance while running
Total distance she covered = 1 + 1.5
Total distance she covered = 2.5 miles

Hope this helps :)

4 0
3 years ago
Antonio has $15 to spend on a set of colored pencils for his art class. Which number line represents the amount that he can spen
Mama L [17]
Answer: A
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I hope this answers your question
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2 years ago
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koban [17]

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\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

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