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raketka [301]
4 years ago
7

Without actually calculating, how much greater is the product of 98x50 than the product of 97x50

Mathematics
2 answers:
gavmur [86]4 years ago
7 0
(98-97)x50=1 x 50=50
98x50 is greater than 97x50 by 50
☺☺☺☺
krek1111 [17]4 years ago
5 0
98x50 is 50 greater than 97x50 because you are multiplying it by 50 one more time.
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Find the equation of the line that passes through the points (3,-2) and (6,-8)
Karolina [17]

Answer:

2x + y = 4

Step-by-step explanation:

The two-point form of the equation of a line is:

y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1)

We have:

x1 = 3

y1 = -2

x2 = 6

y2 = -8

Plug in all the values where they belong in the equation above.

y - (-2) = \dfrac{-8 - (-2)}{6 - 3}(x - 3)

Simplify.

y + 2 = \dfrac{-6}{3}(x - 3)

y + 2 = -2(x - 3)

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so...
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Why the commutative and associative properties don't hold true for subtraction and division
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Answer:

how many yards does each piece have to be

Step-by-step explanation:

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3 years ago
Sophia has an ear infection. The doctor prescribes a course of antibiotics. Sophia is told to take 500 mg doses of the antibioti
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Answer:

Step-by-step explanation:

Part 1:

Let 

     Q₁ = Amount of the drug in the body after the first dose.

     Q₂ =  250 mg

As we know that after 12 hours about 4% of the drug is still present in the body.

For Q₂,

we get:

            Q₂ = 4% of Q₁ + 250

                  = (0.04 × 250) + 250

                  = 10 + 250

                  = 260 mg

Therefore, after the second dose, 260 mg of the drug is present in the body.

Now, for Q₃ :

We get;

          Q₃ = 4% of Q2 + 250

               = 0.04 × 260 + 250

               = 10.4 + 250

               = 260.4

For Q₄,

We get;

          Q₄ = 4% of Q₃ + 250 

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Part 2:

To find out how large that amount is, we have to find Q₄₀.

Using the similar pattern

for Q₄₀,

We get;

           Q₄₀ = 250 + 250 × (0.04)¹ + 250 × (0.04)² + 250 × (0.04)³⁹

Taking 250 as common;

           Q₄₀ = 250 (1 + 0.04 + 0.042 + ⋯ + 0.0439)

                 = 2501 − 0.04401 − 0.04

           Q₄₀ = 260.4167

Hence, The greatest amount of antibiotics in Susan’s body is 260.4167 mg.

Part 3:

From the previous 2 components of the matter, we all know that the best quantity of the antibiotic in Susan's body is regarding 260.4167 mg and it'll occur right once she has taken the last dose. However, we have a tendency to see that already once the fourth dose she had 260.416 mg of the drug in her system, that is simply insignificantly smaller. thus we will say that beginning on the second day of treatment, double every day there'll be regarding 260.416 mg of the antibiotic in her body. Over the course of the subsequent twelve hours {the quantity|the quantity|the number} of the drug can decrease to 4% of the most amount, that is 10.4166 mg. Then the cycle can repeat.

3 0
4 years ago
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