Answer:
B, coefficient vertically stretches or compress not horizontally, plus it is negative so x axis dlip
Answer:
average atomic mass = 207.2172085 amu
Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.
For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)
The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
+ 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu
Hope this helps :)
Well that symbol is an indention or multiply sign of expression
Answer:
m<1 = 1/2(a+b)
Step-by-step explanation:
First, you have to add the two different side angles and then divide by two. I just took my quiz and got this.
Answer:
Domain is that interval in which the function is defined ....
So this function is defined everywhere except 4 and 7 ,
option D is correct....
