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Yanka [14]
3 years ago
10

A function is shown. f(x)=x2+2x−1 Which graph represents the function?

Mathematics
1 answer:
neonofarm [45]3 years ago
6 0
It's the bottom answer
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-2^x+3=-3^-x-2 solve for x
Sindrei [870]

Answer:

x = 2.34373881

There you go

8 0
3 years ago
Describe how you would find the maximum and minimum values for tangent of the typical angles used on the unit circle. What are t
Ipatiy [6.2K]

<span>3down votefavorite1Find minimum and maximum value of function <span>f(x,y)=3x+4y+|x−y|</span> on circle<span>{(x,y):<span>x2</span>+<span>y2</span>=1}</span>I used polar coordinate system. So I have <span>x=cost</span> and <span>y=sint</span> where <span>t∈[0,2π)</span>.Then i exploited definition of absolute function and i got:<span>h(t)=<span>{<span><span>4cost+3sintt∈[0,<span>π4</span>]∪[<span>54</span>π,2π)</span><span>2cost+5sintt∈(<span>π4</span>,<span>54</span>π)</span></span></span></span>Hence i received following critical points (earlier i computed first derivative):<span>cost=±<span>45</span>∨cost=±<span>2<span>√29</span></span></span>Then i computed second derivative and after all i received that in <span>(<span>2<span>√29</span></span>,<span>5<span>√29</span></span>)</span> is maximum equal <span>√29</span> and in <span>(−<span>45</span>,−<span>35</span>)</span> is minimum equal <span>−<span>235</span></span><span>
</span></span>
6 0
3 years ago
Solve<br> 4(x + 3) = 6<br><br> Make x the subject
Irina-Kira [14]

Answer:

x = -3/2

Step-by-step explanation:

4(x + 3) = 6

4x + 12 = 6

4x = 6 - 12

4x = -6

x = -6/4

x = -3/2

5 0
3 years ago
Read 2 more answers
Use the grouping method to factor x^3+x^2+5x+5
Marianna [84]

Answer: MARK BRAINLIEST

23x

Step-by-step explanation:

x^3+x^2+5x+5 = 23x

6 0
3 years ago
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A researcher claims that the average body mass index (BMI) of adult Canadians is more than 25.0. He takes a SRS of 250 Canadians
Serjik [45]

Answer:

The probability of obtaining a result equivalent to or greater than what was the truly observed value of the test statistic is 0.001.

Step-by-step explanation:

The researcher can use a one sample <em>z</em> test to determine whether his claim is correct or not.

The hypothesis to test whether the mean BMI is more than 25.0, is defined as:

<em>H₀</em>: The mean BMI is not more than 25.0, i.e. <em>μ </em>≤ 25.0.

<em>Hₐ</em>: The mean BMI is more than 25.0, i.e. <em>μ </em>> 25.0.

The test statistic is defined as:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}

The <em>p</em>-value of the test is,

<em>p</em> = 0.001.

The p-value is well-defined as per the probability, [under the null-hypothesis (<em>H₀</em>)], of attaining a result equivalent to or greater than what was the truly observed value of the test statistic.

A small p-value (typically ≤ 0.05) specifies sufficient proof against the null hypothesis (<em>H₀</em>), so you discard <em>H₀</em>. A large p-value (> 0.05) specifies fragile proof against the <em>H₀</em>, so you fail to discard <em>H₀.</em>

The <em>p</em>-value of 0.001 indicates that the probability of obtaining a result equivalent to or greater than what was the truly observed value of the test statistic is 0.001.

As the <em>p</em>-value is very small, the null hypothesis will be rejected at any level of significance.

Thus, concluding that the mean BMI of adult Canadians is more than 25.0.

3 0
3 years ago
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