Please help!!! Verify which of the following are identities.
1 answer:
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Answer:
The given function is a nonlinear function because the degree of the function is 2 and we get same value of y for more than one values of x.
Step-by-step explanation:
The given function is
To find the points which lie on the function, put difference values of x in the given function and find the values of y.
Put x= -2
Put x= -1
Put x= 0
Put x=1
Put x= 2
The table of values is shown below.
Plot these points on a coordinate plane and connect them by a free hand curve.
The given function is a nonlinear function because the degree of the function is 2 and we get same value of y for more than one values of x.
The graph of function is shown below.
Answer: at the values where cos(x) = 0
Justification:
1) tan(x) = sin(x) / cos(x).
2) functions have vertical asymptotes at x = a if Limit of the function x approaches a is + or - infinity.
3) the limit of tan(x) approaches +/- infinity where cos(x) approaches 0.
Therefore, the grpah of y = tan(x) has asymptotes where cos(x) = 0.
You can see the asympotes at x = +/- π/2 on the attached graph. Remember that cos(x) approaches 0 when x approaches +/- (n+1) π/2, for any n ∈ N, so there are infinite asymptotes.
Justification:
1) tan(x) = sin(x) / cos(x).
2) functions have vertical asymptotes at x = a if Limit of the function x approaches a is + or - infinity.
3) the limit of tan(x) approaches +/- infinity where cos(x) approaches 0.
Therefore, the grpah of y = tan(x) has asymptotes where cos(x) = 0.
You can see the asympotes at x = +/- π/2 on the attached graph. Remember that cos(x) approaches 0 when x approaches +/- (n+1) π/2, for any n ∈ N, so there are infinite asymptotes.