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Dominik [7]
4 years ago
15

The base of a triangle is 2 ft. The

Mathematics
2 answers:
EleoNora [17]4 years ago
7 0

Answer:

180inches^2

Step-by-step explanation:

please give me the brainliest I have tried hard to answer this question

have a great day!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

12*2= 24

24*15=360

360/2= 180

area = 180

n200080 [17]4 years ago
3 0

Answer: The area of the triangle is 180 square inches

Step-by-step explanation: The question gives us a triangle with the dimensions as

Base = 2 feet

Height = 15 inches

However the answer should be expressed in inches, which means we have to convert the measurements in feet to inches. Remember that 12 inches make one foot. Therefore, two feet would simply be

12 x 2

= 24 inches

With the dimensions now given as

Base = 24 inches

Height = 15 inches

Area of the triangle = ½B x H

Area of the triangle = ½ x 24 x 15

Area of the triangle = 12 x 15

Area of the triangle = 180 square inches

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What is the solution to the inequality x+(7+2x)≤−3x?
3241004551 [841]

Answer:

don't press that link

Step-by-step explanation:

8 0
3 years ago
The quadratic function modeling the helght of a ball over time is symmetric about the line t = 2.5, where is lite
mina [271]

Answer:

The height of the ball is the same after 1.5 seconds and 3.5 seconds. ⇒ (A)

Step-by-step explanation:

<em>The quadratic function is represented by a parabola</em>

  • The parabola is symmetric about its vertex.
  • The average of the x-coordinates of any opposite points (points have the same y-coordinates) on the parabola is equal to the x-coordinate of its vertex point.
  • The axis of symmetry of it passes through the x-coordinate of its vertex point.
  • The equation of its axis of symmetry is x = h, where h is the x-coordinate of its vertex point.

∵ The quadratic function modeling the height of a ball over time

∴ f(t) = at² + bt + c

→ t is the time in second, f(t) is the height of the ball after t seconds

∵ It is symmetric about the line t = 2.5

∴ The x-coordinate of its vertex is 2.5

→ That means the average of the x-coordinates of any two

   opposite points belong to f(t) is 2.5

∵ The average of 1.5 and 3.5 = \frac{1.5+3.5}{2}=\frac{5}{2}=2.5

∴ 1.5 and 3.5 have the same value of f(t)

∴ 1.5 and 3.5 have the same height

The height of the ball is the same after 1.5 seconds and 3.5 seconds.

4 0
3 years ago
line m contains the points -3,4 and 1,0. write the equation of a line that would be perpendicular to this one and pass through t
castortr0y [4]

The equation of line perpendicular to line containing points (-3, 4) and (1, 0) and passes through (-2, 6) in point slope form is y = x + 8

<h3><u>Solution:</u></h3>

Given that line m contains points (-3, 4) and (1, 0)

We are asked to find the equation of line perpendicular to line containing points (-3, 4) and (1, 0) and passes through (-2, 6)

<em><u>Let us first find slope of the line "m"</u></em>

Given two points are (-3, 4) and (1, 0)

m = \frac{y_2 - y_1}{x_2 - x_1}

\left(x_{1}, y_{1}\right)=(-3,4) \text { and }\left(x_{2}, y_{2}\right)=(1,0)

m=\frac{0-4}{1-(-3)}=-1

Thus slope of line m is -1

We know that <em>product of slope of given line and perpendicular line are always -1</em>

So, we get

\begin{array}{l}{\text { slope of line } m \times \text { slope of perpendicular line }=-1} \\\\ {-1 \times \text { slope of perpendicular line }=-1} \\\\ {\text { slope of perpendicular line }=1}\end{array}

So we have got the slope of perpendicular line is 1 and it passes through (-2, 6)

Let us use the point slope form to find the required equation

<em><u>The point slope form is given as:</u></em>

y - y_1 = m(x - x_1)

(x_1, y_1) = (-2, 6) and m = 1

y - 6 = 1(x - (-2))

y - 6 = x + 2

y = x + 8

Thus equation of required line in point slope form is y = x + 8

7 0
3 years ago
There was a total of $9.48 million contributed to a political campaign by 79 thousand people. What was the average contribution?
IrinaK [193]
The average was $120
3 0
3 years ago
Hank brought a fish tank
SIZIF [17.4K]
I think the answer is 1,200

3 0
3 years ago
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