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ioda
2 years ago
6

When you find 100% of a number, how does your answer relate to the original number?

Mathematics
2 answers:
snow_lady [41]2 years ago
7 0

Answer:

i think c.

Step-by-step explanation:


Marysya12 [62]2 years ago
5 0

The numbers are equal (choice A)

This is because 100% of something is that entire thing, not changed at all. It is not added to, or subtracted from. Example: 100% of 78 is 78. If you had 78 people in a room, and selected 100% of them, then you selected all 78 people.

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The height h of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the funct
Vika [28.1K]

Answer:

D) h(3)-h(0)/3

Step-by-step explanation:

The average rate of change is found by subtracting the output values (finding the amount of change in the output values) and dividing it by the change in the input values.

The height in the 3rd second would be given by h(3).  The original height would be given by h(0).  The change in output values would be given by h(3)-h(0).

The change in input values is found by subtracting the two input values, in this case 3 and 0; 3-0 = 3.  

This gives us

h(3)-h(0)/3

6 0
3 years ago
Read 2 more answers
Find inverse of f(x)=3x+1
Ratling [72]
First, replace f(x) with y.

So we have now:

y = 3x + 1

Next, switch the x and y.

We get:

x = 3y + 1

Finally, solve for y.

3y = x - 1

y = x/3 - 1/3

So, we have f(x) = 3x + 1, and the inverse of this function is:

\boxed{f^{-1}(x) = \frac{1}{3} x - \frac{1}{3}}\\\\OR\\\\\boxed{f^{-1}(x) = \frac{x-1}{3}}
6 0
2 years ago
Which of the following is a linear function?<br> А<br> B<br> C<br> D
kramer

Answer:

d

Step-by-step explanation:

..................

3 0
2 years ago
How do you solve 4y^-3-x^2y^-1?
Lerok [7]
4y^-3 - x^2y^-1 = 2y^-1(2y^-2 - x^2)
8 0
2 years ago
18. Use limits to find the area between the graph of the function and the x axis given by the definite integral. ∫_1^5·(x^2-x+1)
Stolb23 [73]

Answer:

\int\limits^5_1 {(x^2-x+1)} \, dx= \frac{100}{3}\approx33.33units^2

Step-by-step explanation:

To determine the area of the definite integral, we take each term and find its corresponding integral. We know that \int\limits {x^n} \, dx =\frac{x^{n+1}}{n+1} +C, so therefore we rewrite the expression as \frac{x^3}{3}-\frac{x^2}{2}+x.

Now, we plug in each limit into the expression and find the difference between them:

(\frac{5^3}{3}-\frac{5^2}{2}+5)-(\frac{1^3}{3}-\frac{1^2}{2}+1)

(\frac{125}{3}-\frac{25}{2}+5)-(\frac{1}{3}-\frac{1}{2}+1)

(\frac{250}{6}-\frac{75}{6}+\frac{30}{6} )-(\frac{2}{6}-\frac{3}{6}+\frac{6}{6})

(\frac{205}{6})-(\frac{5}{6})

\frac{200}{6}

\frac{100}{3}

Therefore, \int\limits^5_1 {(x^2-x+1)} \, dx= \frac{100}{3}\approx33.33units^2

7 0
2 years ago
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