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stellarik [79]
3 years ago
13

Write the equation of the line that passes through the points (1,4) and (5,8) in standard form.

Mathematics
2 answers:
ololo11 [35]3 years ago
7 0
D is your answer

plug in the x value and y value to the equation

when x = 1, and y = 4
-1 + 4 = 3

when x = 5, and y = 8
-5 + 8 = 3

hope this helps :D
Maru [420]3 years ago
6 0
Hi again Mr. Joseph!

Well, the correct answer is option D

-------------------------------------------------
We need to find the equation using two points.

But the trick is that you need to solve for y but not x
So let's solve for y
 - x + y = 3
Add x to both sides (Why? because we don't want x, so we need to get it out)
-x + y + x = 3 + x
y = x + 3
That's the correct equation.

They gave us (1,4)(5,8)
Use the slope formula and slope intercept form.
Do you know what the formula is?
Well, it looks like this
y = mx +b

So yeah, when we do all of that, we ended up having -x + y =3

Once again,
The correct answer is D

Best of luck with your studies!

Credit to my graphing calculator, here is how the points looks like on the graph


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3 0
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11/ 42 Marks
amm1812

Answer:

(a)x=128 degrees

(b)\angle APD\neq 116^\circ

Step-by-step explanation:

\angle ABD+\angle CBD =180^\circ$ (Linear Postulate)\\\angle ABD+116^\circ =180^\circ\\\angle ABD=180^\circ-116^\circ\\\angle ABD=64^\circ

(a) Now:

\angle AOD=2 \times \angle ABD$ (Angle at the centre is twice the  angle at the circumference)\\x=2 \times 64^\circ\\x=128^\circ

(b)

\angle APD=2 \times \angle ABD$ (Inscribed Angle Theorem)\\\angle APD=2 \times 64^\circ\\ \angle APD=128^\circ

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7 0
3 years ago
Choose one of the factors of x^3 + 343.
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Therefore,

x^3 + 343=x^3+7^3=(x+7)(x^2-7x+49).

The quadratic trinomial x^2-7x+49 couldn't be factored anymore, so the expression x^3 + 343 has two factors x+7 and x^2-7x+49.

Answer: correct choice is A.

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