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sertanlavr [38]
3 years ago
9

A plumbing bill was $200. This included $50 for parts and $25 per hour for labor. Find the number of hours of labor.

Mathematics
2 answers:
victus00 [196]3 years ago
8 0

Answer:

6 hrs. of labor

Step-by-step explanation:

200-50= 150

150/25= 6

pogonyaev3 years ago
6 0

Answer:

6 hours

Step-by-step explanation:

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In a random sample of 380 cars driven at low altitudes, 42 of them exceeded a standard of 10 grams of particulate pollution per
alexdok [17]

Answer:

The test statistic for testing if the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard is 3.234.

Step-by-step explanation:

We are given that in a random sample of 380 cars driven at low altitudes, 42 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed.

In an independent random sample of 90 cars driven at high altitudes, 24 of them exceeded the standard.

Let p_1 = <u><em>population proportion of cars driven at high altitudes who exceeded a standard of 10 grams</em></u>.

p_2 = <u><em>population proportion of cars driven at low altitudes who exceeded a standard of 10 grams</em></u>.

So, Null Hypothesis, H_0 : p_1\leq p_2      {means that the proportion of high-altitude vehicles exceeding the standard is smaller than or equal to the proportion of low-altitude vehicles exceeding the standard}

Alternate Hypothesis, H_A : p_1>p_2      {means that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard}

The test statistics that will be used here is <u>Two-sample z-test statistics</u> for proportions;

                             T.S.  =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~  N(0,1)

where, \hat p_1 = sample proportion of cars driven at high altitudes who exceeded a standard of 10 grams = \frac{24}{90} = 0.27

\hat p_2 = sample proportion of cars driven at low altitudes who exceeded a standard of 10 grams = \frac{42}{380} = 0.11

n_1 = sample of cars driven at high altitudes = 90

n_2 = sample of cars driven at low altitudes = 380

So, the test statistics =  \frac{(0.27-0.11)-(0)}{\sqrt{\frac{0.27(1-0.27)}{90}+\frac{0.11(1-0.11)}{380} } }      

                                   =  3.234

The value of z-test statistics is 3.234.

7 0
3 years ago
What is the domain of f/g given f(x) = x+4 and g(x) = x-1
Butoxors [25]

Answer:   the domain of f/g is every real number except 1 which can be conventionally expressed as {(x,y): <em>x</em> ∈ R, x ≠ 1} OR (-∞ ≤ x < 1) ∩ (1< x ≤ ∞) OR x ∈ R; x ≠ 1.

Step-by-step explanation:

since f(x) = x + 4 and g(x) = x -  1

then f/g = x + 4/x - 1

the denominator of a function cannot be zero since a fraction with a denominator of zero is undefined.

∴  x - 1 ≠ 0

the value of x when g(x) = 0 is

       x - 1 = 0

       x = 1

∴ x ≠ 1

Therefore the domain of f/g is every real number except 1 which can be conventionally expressed as {(x,y): <em>x</em> ∈ R, x ≠ 1} OR (-∞ ≤ x < 1) ∩ (1< x ≤ ∞) OR x ∈ R; x ≠ 1.

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3 years ago
188,888*1000 ???????<br><br><br><br> really need help!!!!!!!!!!!!!!!!!!!!!!!
d1i1m1o1n [39]
<h3>The answer is :-</h3>

188,888,000

<h3>Explanation :- </h3>

We have to multiply 188,888 by 1000

so just add the zeros after 188,888

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2 years ago
Sketch the graph of y =sine3x​
IgorLugansk [536]

The graph of \mathbf{y=\sin{3x}} is given by,

Here given the function is y=\sin{3x}

when x=0\Rightarrow y=\sin{3\times 0}=\sin0=0, then it passes through the origin (0,0).

When x=\frac{\pi}{6}\Rightarrow y=\sin{3\times\frac{\pi}{6}}=\sin\frac{\pi}{2}=1

Since we know that, -1\leq\sin{x}\leq1,\forall x, then the function has maximum height at x=\frac{\pi}{6}.

Again when x=\frac{\pi}{3}\Rightarrow y=\sin{(3\times\frac{\pi}{3})}=\sin\pi=0, again the function is 0.

So clearly the function is the Oscillating function.

Using graphing calculator we get the graph of function y=\sin3x,

Learn more about Trigonometric Function here -

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Hector and Francis a spent total of $47.50 at the mall. If Hector spent 50% more than Francis, how much did Francis spend at the
Zigmanuir [339]
Francis spent $19 and Hector spent $28.50
5 0
3 years ago
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