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Diano4ka-milaya [45]
3 years ago
15

Suppose babies born after a gestation period of 32 to 35 weeks have a mean weight of 2500 grams and a standard deviation of 800

grams while babies born after a gestation period of 40 weeks have a mean weight of 2800 grams and a standard deviation of 425 grams. If a 33​-week gestation period baby weighs 2600 grams and a 41​-week gestation period baby weighs 2900 ​grams, find the corresponding​ z-scores. Which baby weighs more relative to the gestation​ period?
Biology
1 answer:
Nesterboy [21]3 years ago
8 0

Answer:

Babies of 33 week weighs relatively less than the babies of 41 week.

Explanation:

Z score is determined by

=\frac{x-u}{SD}

A) For 33 Week baby

Given

Mean = 2500

SD= 800

x=2600

Z score is

\frac{2600-2500}{800} \\= 0.125

B) For 41 Week baby

Given

Mean = 2800

SD= 425

x=2900

Z score is

\frac{2900-2800}{425} \\= 0.235

The z score depicts that the baby of 33 week or 41 week weighs more than the normal babies of same age group.

Thus, babies of 33 week weighs relatively less than the babies of 41 week.

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You perform the following dihybrid cross: A blaBx Ab/aB. The A and B genes control different traits. What phenotypic ratio would
Luda [366]

Answer:

Option-D

Explanation:

In the given question the genotype of parental allele is- AbaB X AbaB. The alleles formed will be- AB, Ab,aB, ab in which the crossover allele will be AB and ab.

1. Unlinked genes

Now of these alleles are unlinked then the alleles will assort independently of each other therefore performing the punnett square we will get dihybrid ratio as 9:3:3:1 in which  

1. A_B_ are 9

2. aaB_ are 3

3. A_bb are-3

4. aabb- 1

Since the crossover allele are AB and ab therefore A_B_ are 9 and aabb- 1 represent recombinant genotype.

2. Linked genes

When the genes will be linked then chances of crossing over will be reduced as a result of which only two type of allele will be formed which are-  Ab and aB and the recombinant frequency will become less.

Crossing these allele will  form Aabb , AaBb , AaBb  and aaBB  genotypes. The recombinant ratio will decrease as A_B_ is 2 and aabb is not present.

Thus, option-4 which states that the unlinked ration is  9:3:3:1  and linked ratio is  <9: >3: >3: <1 is correct.

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