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miskamm [114]
4 years ago
9

Given a double variable named areaofsquare write the necessary code to read in a value , the area of some square, into areaofsqu

are and print out the length of the side of that square. however: if any value read in is not valid input, just print the message "invalid". assume the availability of a variable , stdin, that references a scanner object associated with standard input.
Computers and Technology
1 answer:
wolverine [178]4 years ago
3 0
I can solve it with Java. Here it is: 

areaOfSquare = stdin.nextDouble();
double sqrt = Math.sqrt(areaOfSquare);
if(Double.isNaN(sqrt)){
     System.out.print("INVALID");
} else {
     System.out.print(sqrt);
}
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Write a string class. To avoid conflicts with other similarly named classes, we will call our version MyString. This object is d
kipiarov [429]

Answer:

Check the explanation

Explanation:

myString. h:

#include <iostream>

using namespace std;

#ifndef _MYSTRING_H_

#define _MYSTRING_H_

class myString{

private:

  char *str;

public:

  myString();

  myString(const char *s);

  void operator = (myString &s);

  int length();

  friend ostream &operator <<(ostream &out, myString &s);

  friend istream &operator >>(istream &out, myString &s);

  bool operator <(myString &s);

  bool operator <=(myString &s);

  bool operator >(myString &s);

  bool operator >=(myString &s);

  bool operator ==(myString &s);

  bool operator !=(myString &s);

};

#endif

myString. cpp:

#include "myString. h"

#include <cstring>

myString::myString(){

  str = new char;

  str[0] = '\0';

}

myString::myString(const char *s){

  int len = strlen(s);

  str = new char[len + 1];

  for(int i = 0; i < len; ++i){

      str[i] = s[i];

  }

  str[len] = '\0';

}

void myString::operator = (myString &s){

  s.str = new char[length() + 1];

  for(int i = 0; i < length(); ++i){

      s.str[i] = str[i];

  }

  s.str[length()] = '\0';

}

int myString::length(){

  return strlen(str);

}

ostream &operator <<(ostream &out, myString &s){

  out << s.str;

  return out;

}

istream &operator >>(istream &in, myString &s){

  in >> s.str;

  return in;

}

bool myString::operator < (myString &s){

  return strcmp(str, s.str) < 0;

}

bool myString::operator <= (myString &s){

  return strcmp(str, s.str) <= 0;

}

bool myString::operator > (myString &s){

  return strcmp(str, s.str) > 0;

}

bool myString::operator >= (myString &s){

  return strcmp(str, s.str) >= 0;

}

bool myString::operator == (myString &s){

  return strcmp(str, s.str) == 0;

}

bool myString::operator != (myString &s){

  return strcmp(str, s.str) != 0;

}

main. cpp:

#include "myString.h"

#include <iostream>

using namespace std;

int main(){

  myString s1, s2;

  cout << "Enter first string: ";

  cin >> s1;

  cout << "Enter second string: ";

  cin >> s2;

  cout << "you entered: " << s1 << " and " << s2 << endl;

  myString s3 = s1;

  cout << "Value of s3 is " << s3 << endl;

  if(s1 < s2){

      cout << s1 << " < " << s2 << endl;

  }

  if(s1 <= s2){

      cout << s1 << " <= " << s2 << endl;

  }

  if(s1 > s2){

      cout << s1 << " > " << s2 << endl;

  }

  if(s1 >= s2){

      cout << s1 << " >= " << s2 << endl;

  }

  if(s1 == s2){

      cout << s1 << " == " << s2 << endl;

  }

  if(s1 != s2){

      cout << s1 << " != " << s2 << endl;

  }

  return 0;

}

Kindly check the output below.

4 0
3 years ago
A​ ___________ identifies the content and purpose of the​ visual, along with whatever label and number​ you're using to refer to
Westkost [7]

Answer:Title

Explanation: Title is basically considered as the "heading" or the "topic" that is used for giving the hint about the content or visual. In context with the visual ,which is the piece of display where title determines about the reason of visual and also hints about the content .It also gives the reference number that a person assign to the visual.

7 0
3 years ago
Hexadecimal to denary gcse method
Anuta_ua [19.1K]

There are two ways to convert from hexadecimal to denary gcse method. They are:

  • Conversion from hex to denary via binary.
  • The use of base 16 place-value columns.

<h3>How is the conversion done?</h3>

In Conversion from hex to denary via binary:

One has to Separate the hex digits to be able to know or find its equivalent in binary, and then the person will then put them back together.

Example - Find out the denary value of hex value 2D.

It will be:

2 = 0010

D = 1101

Put them them together and then you will have:

00101101

Which is known to be:

0 *128 + 0 * 64 + 1 *32 + 0 * 16 + 1 *8 + 1 *4 + 0 *2 + 1 *1

= 45 in denary form.

Learn more about hexadecimal from

brainly.com/question/11109762

#SPJ1

3 0
2 years ago
Special numeric has three digits and holds a property that it is exactly equal to summation of cubes from each digit. For exampl
Vera_Pavlovna [14]

Answer:

The following code is written in C programming language:

#include <stdio.h>     //header file

 

int main()       //main method

{

   int n, t, digit1, digit2, digit3;      // set integer variables

    // print message

   printf("Print all Special integer numbers between 100 and 999:\n");

   n = 100;      //initialize value in variable "n"    

   while (n <= 999)      //set while loop

   {

       digit1 = n - ((n / 10) * 10);

       digit2 = (n / 10) - ((n / 100) * 10);

       digit3 = (n / 100) - ((n / 1000) * 10);

       t = (digit1 * digit1 * digit1) + (digit2 * digit2 * digit2) + (digit3 * digit3 * digit3);

       if (t == n)      //set if statement

       {

           printf("\n Special integer number is: %d", t);     //print an output

       }

       n++;

   }

}

Output:

Print all Special integer numbers between 100 and 999:

Special integer number is: 153

Special integer number is: 370

Special integer number is: 371

Special integer number is: 407

Explanation:

Here, we set the header file "stdio.h".

Then, we define integer type "main()" function.

Then, we set five integer type variable "n", "t", "digit1", "digit2", "digit3".

Then, we the print message by print() method and initialize a value to variable "n" to 100.

Then, we set the while loop which starts from 100 and stops at 999 and if the condition is true than code inside the loop is execute either loop is terminated.

Then, we set the if statement and pass the condition, if the condition is true the output would be print either if the condition is false the if statement is terminated.

8 0
3 years ago
PA theme is a major message that a writer convoys through a text. you have explored many themes in the hobbit one theme in the n
Nataly [62]

Answer:

The Hobbit’s main theme is Bilbo’s development into a hero, which more broadly represents the development of a common person into a hero. At the beginning of the story, Bilbo is timid, comfortable, and complacent in his secure little hole at Bag End. When Gandalf talks him into embarking on the quest with Thorin’s dwarves, Bilbo becomes so frightened that he faints. But as the novel progresses, Bilbo prevails in the face of danger and adversity, justifying Gandalf’s early claim that there is more to the little hobbit than meets the eye.??????

Explanation:

7 0
3 years ago
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