The answer is A) hope that this will help you
Answer:
c. Elasticity
Explanation:
When referring to Cloud Servers this capability is known as Elasticity. It basically describes how able and efficient a server is to automatically implement resources and remove resources in order meet the specific amount of demand at any given moment. Many times a server will not have much demand but will still have all the resources being used by the server. Being able to remove these unused resources so that they are available for other usage is what makes the servers elastic.
Answer:
Explanation:
Denote the five numbers as a, b, c, d and e.
The average is:
(a + b + c + d +e) ÷ 5.
Easily:
Learn how to do input and output operations in your programming language of choice.
Learn what average is (see Arithmetic mean - Wikipedia)
Learn how to code arithmetic operations in your PL of choice.
Put all that together and code the program.
Oh, did you expect the code snippet? Sorry, I don’t do peoples’ homework for them on principle. Homework is for you to learn something. If you can’t be bothered, accept that you’ll fail your class. If you want to pass, LEARN.
Answer:
Total Memory= 4 KB = 4096 bytes = 32768 bits
Explanation:
<em><u>1. Data lines are 8 From D0 to D7</u></em>
so
Total memory at single address locations is 8 bits.
<em><u>2. Address lines are 12 (A0 to A11)</u></em>
There are 12 address lines but 3 out 12 are for selction of chip or memory bank.
so only 9 pins are there to address the locations on one chip.
Total No. of address locations on single chip = 2^9 = 512 locations
as 1 location is 1 byte so total memory of single chip is 512 bytes.
<u><em>3. Total Memory Bank </em></u>
There are total 3 selection pins for memory bank.
so
Total chips = 2^3 = 8.
<em><u>4. Total Memory </u></em>
Total size of 1 chip = 512 bytes
Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb
<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>
