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3 years ago

In what year 200, the population of Virginia was about 7,400,000.

2 answers:

8 0

For this case we have the following function:
f (x) = 7,400,000 (1,054) ^ x
Where,
x represents time in years.
Substituting f (x) = 15000000 we have:
15000000 = 7,400,000 (1,054) ^ x
Clearing x we have:
(1,054) ^ x = (15000000) / (7400000)
log1.054 ((1.054) ^ x) = log1.054 ((15000000) / (7400000))
x = log1.054 ((15000000) / (7400000))
x = 13.4 years
Rounding to the nearest year:
x = 14 years
Answer:
the population will reach 15,000,000 in 2014.

bazaltina [42]3 years ago

8 0

Answer:

ur hot

Step-by-step explanation:

im in love

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Answer:

Since the question is partial, i will assume 2 scenarios:

They need to raise 1000 income

They need to make 1000 as profit

If $1000 as income:

Each ticket costs $15, so tickets would bring them $1000 income. Fractional ticket is not possible, so rounding gives us 67 tickets as the answer.

If $1000 as profit:

Their cost of renting is $700. We know that .

So, . So, to raise $1700, we need tickets. Fractional ticket is not possible, so rounding gives us 114 tickets as the answer.

ANSWER:

If need to raise atleast $1000 as income, they need to sell 67 tickets.

If need to raise atleast $1000 as profit, they need to sell 114 tickets.

The most probable answer would be 114 tickets

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3 years ago

twenty students in A and 20 students in class B were asked how many hours they took to prepare for an exam.The data sets represe

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Answer:

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Step-by-step explanation:

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3 years ago

A jar contains 37 marbles of which 13 marbles are blue 10 red and rest are green. what is the ratio of green marbles to red marb

jeka94

37=blue+red+green
37-red-blue=green
37-13=10=green
14=green

green:red=
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3 years ago

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Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

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3 years ago

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