Answer:
15.0
Step-by-step explanation:
Let's start by looking at triangle ORQ. Since RQ is tangent to the circle, we know that angle ∠ORQ is 90°. Then, since OR is equivalent to the radius of 5, RQ is 5√3, and side OQ is clearly larger than RQ, we can identify this as a 90-60-30 degree triangle. This makes side OQ have a length of 10, and angle ∠QOR, opposite of the second largest side, has the second largest angle of 60°, leaving ∠OQR with an angle of 30°.
The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)
Answer:
r=2
Step-by-step explanation:
r + 8 r + 11 = 29
( 1 + 8 ) r + 11 = 29 9 r + 11 = 29
Now we can isolate and solve for r while always keeping the equation balanced: First, subtract 11 from each side of the equation:
9 r + 11 − 11 = 29 − 11
9 r + 0 = 18
9 r = 18
Now we can divide each side of the equation by 9 to get
r : 9 over 9 = 18 under 9
1 r = 2
r = 2
Answer:
80,00
Step-by-step explanation:
According to my research, the formula for the Area of a rectangle is the following,

Where
- A is the Area
- L is the length
- W is the width
Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>
800 / 2 = 400ft
So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.
400/2 = 200 ft
Now we can calculate the maximum Area using the values above.


So the Maximum area we are able to create with 800 ft of fencing is 80,00
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To solve this problem just do the following,
x+9=-12
-9 -9
x=-21
Check
-21+9=-12 = True
Hope this helps!=)