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evablogger [386]
3 years ago
13

Crickets can jump with a vertical velocity of up to 14 ft/s. Which equation models the height of such a jump, in feet, after t s

econds?
h(t) = –16t2 + v0t + h0


h(t) = –16t2 + v0t + 14

h(t) = –16t2 + 14t

h(t) = –16t2 + 14t + 14
Mathematics
2 answers:
Strike441 [17]3 years ago
7 0

B is your answer I just took the assignment quiz.

Charra [1.4K]3 years ago
6 0

Answer:

h(t) = -16t^2 + 14t

Step-by-step explanation:

Crickets can jump with a vertical velocity of up to 14 ft/s

General equation is

h(t) = -16t^2 + v_0(t) + h_0

Where v0 is the initial velocity

h0 is the initial height

velocity is 14 ft/s

initial height is not given so h0=0

h(t) = -16t^2 + v_0(t) + h_0

h(t) = -16t^2 + 14t + 0

h(t) = -16t^2 + 14t

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A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte
AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

\angle SPR=Angle subtended by the statue to where you are standing.

\angle x=\angle RPQ= which is unknown.

Let us begin solving now. The first step is to find the angle \angle x which can be found by using the following trigonometric ratio in \Delta PQR :

tan(x)=\frac{RQ}{PQ} =\frac{21}{57}

Which gives \angle x to be:

\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}

Now, we know that\angle x and \angle SPR can be added to give us the complete angle \angle SPQ in the right triangle \Delta SPQ.

We can again use the tan trigonometric ratio in \Delta SPQ to solve for the height of the statue, h.

This can be done as:

tan(\angle SPQ)=\frac{SQ}{PQ}

tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}

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3 years ago
Find the percent cost of the total spent on each equipment $36, fees $158, transportation $59
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Percent cost of the total spent on

each equipment = 14.23%,fees=62.45% and transportation = 23.32%.

As given in the question,

Money spent on

Each equipment = $36

Fees = $158

Transportation = $59

Total money spent = $( 36 + 158 + 59)

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Percent cost of the total spent on

Each equipment = (36/253) × 100

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Fees = (36/253) × 100

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Transportation =(36/253) × 100

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