DIFFERENTIATION
6+f(28+b(4)=6+112f+4bf
b=6+112f/-4f
b=1*6^0+1*112f^0/1*-4f^0
b=1+1/1
b=2
Answer: the service charge per hour for premium services is $5.5
the service charge per hour for regular services is $3
Step-by-step explanation:
Let x represent the service charge per hour for premium services.
Let y represent the service charge per hour for regular services.
One customer was charged $38 after spending 2 h in premium areas and 9 regular hours. It means that
2x + 9y = 38- - - - - - - - - - - 1
Another customer spent 3 h in premium areas and 6 regular hours and was charged $34.50. It means that
3x + 6y = 34.5- - - - - - - - - - -2
We would eliminate x by multiplying equation 1 by 3 and equation 2 by 2. It becomes
6x + 27y = 114
6x + 12y = 69
Subtracting, it becomes
15y = 45
y = 45/15
y = 3
Substituting y = 3 into equation 1, it becomes
2x + 9 × 3 = 38
2x + 27 = 38
2x = 38 - 27 = 11
x = 11/2 = 5.5
Answer:
x = 2, y = -1
Step-by-step explanation:
Now change the equation,
→ x + y = 1
→ y = 1 - x
Then the value of x will be,
→ 2x + y = 3
→ 2x + 1 - x = 3
→ x = 3 - 1
→ [ x = 2 ]
Therefore, the value of x is 2.
Now value of y will be,
→ y = 1 - x
→ y = 1 - 2
→ [ y = -1 ]
Hence, the value of y is -1.
The answer to your algerbra question is eight over y
