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Paul [167]
3 years ago
11

Larry says all numbers that have a 2 in their ones place are composite. Explain if Larry is correct or incorrect.

Mathematics
1 answer:
inysia [295]3 years ago
4 0

Answer:

Larry would be wrong if 2(as a prime number) is part of the numbers that has 2 at its ones place, but if 2 is not there, then he is correct.

Step-by-step explanation:

Firstly, we need to know what a composite number is. In simple terms, a composite number is a number that is not a prime number. Meaning that, if a number has more than two factors (1 and itself which is the definition for a prime number), then the number is a composite number.

Larry says all numbers that have 2 in their ones place are composite. It depends, if 2 is the only number that makes up the digit, that is the number itself is 2, then it's obviously a prime number. But any other number having 2 at its ones place is definitely a composite number because the number has more than 2 factors; 1, itself and 2. Example:

12, some of the factors is 1, 12 and 2. Therefore it is a composite number.

Larry would be wrong if 2(as a prime number) is part of the numbers that has 2 at its ones place, but if 2 is not there, then he is correct.

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The product of a number and -7 is 63
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Given the function f(x) = –5|x + 1| + 3, for what values of x is f(x) = –12?
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Let f(x) = 1/x . Find the number b such that the average rate of change of f on the interval [2, b] is − 1/8
vekshin1

Answer:

b=4

Step-by-step explanation:

So, we have the function f(x)=1/x. We need to find b such that the average rate of change or the slope is -1/8 between the intervel [2, b]. First, let's find f(2).

f(2) = 1/(2) = 1/2

So, we have the point (2, 1/2)

At point b, f(b) = 1/b.

Let's plug this into the slope formula:

\frac{y_2-y_1}{x_2-x_1}=\frac{.5-\frac{1}{b} }{2-b}  =-1/8

Now, we just need to solve for b. First, let's multiply both the numerator and denominator by b (to get rid of the annoying fraction in the numerator).

\frac{.5b-1}{2b-b^2} =\frac{-1}{8}

Now, cross multiply.

4b-8=b^2-2b

b^2-6b+8=0

Solve for b. Factor using the numbers -4 and -2.

=(b-4)(b-2)=0

Thus, b=4 or b=2.

However, b=2 is not a possible solution since the interval [2,2] means nothing. Thus, b=4.

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3 years ago
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