For the first, simply plug in the value of x given (x = 2) into the equation: 
So, 8 would be your answer.
For the second, the sum of x and 2 would be expressed as x + 2. Twice this sum would be written as 2(x+2). Finally, 8 less than twice that sum would be written as 2(x+2) - 8, which would be your expression.
For the last question, the coefficient refers to the number directly in front of the variable, x. So you need only to check what the x would simplify to in each equation and look for the expression where x has no coefficient (i.e., its coefficient is 1). For Hunter, the coefficient would be 15 (5 × 3x = 15x); for Michael, the coefficient would be 11 (6x + 5x = 11x); for Nate, the coefficient would be 1 (x = 1x); and for Spencer, the coefficient would be 2 (2x = 2x). Thus, Nate's expression has a coefficient of 1 when simplified.
answer: 5.34
Step by step explanation 12.75 + 13.95=26.7
20% of 26.7 is 5.34
I can’t understand why everyone complicates this question. It can be easily solved by similar triangles.
In this png, we have something to make sure.
∠B=∠DAB
∠
B
=
∠
D
A
B
(Yes, dab)
This also means AD=BD
A
D
=
B
D
.
This is our basic construction of D, which is going to help us.
∠ADC=∠DAB+∠B=2∠B=∠CAB
∠
A
D
C
=
∠
D
A
B
+
∠
B
=
2
∠
B
=
∠
C
A
B
∠CAD=∠CAB−∠DAB=∠B
∠
C
A
D
=
∠
C
A
B
−
∠
D
A
B
=
∠
B
These are based on the fact that ∠A=2×∠B
∠
A
=
2
×
∠
B
Actually these conditions suffice. Because I am just proving that △ACD∼△BCA
△
A
C
D
∼
△
B
C
A
Similarity makes us realize the following:
ACBC=ADAB
A
C
B
C
=
A
D
A
B
and
ACBC=CDAC
A
C
B
C
=
C
D
A
C
So
AC×AB=BC×AD
A
C
×
A
B
=
B
C
×
A
D
and
AC2=BC×CD
A
C
2
=
B
C
×
C
D
So
BC2=BC×(BD+CD)=BC×(AD+CD)
B
C
2
=
B
C
×
(
B
D
+
C
D
)
=
B
C
×
(
A
D
+
C
D
)
=AC×AB+AC2
=
A
C
×
A
B
+
A
C
2
Q.E.D.
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Set this up as a proportion.
400/15 = x/6
Solve for x.
I just hope to help! :)
Initial value can mean many things, but what I believe it means in this area is the value that you start with (obviously), so in the equation (y=mx+b), the initial value is the b. It is where the line intercepts the y-axis, and that is your initial value, I believe!
I hope this was helpful and answered your inquiry! If you have any further doubts or questions, please let me know so that I can help you!
