Let S = {1,2,3,4,5,6,7,8,9,10} be the set of equally likely outcomes for an event. Let event E = {1,2,3,4,5,6} and event F = {2,
Ganezh [65]
Answers:
0.3= P( E AND F ^c)
0.4 = P(F) and P(E^c)
0.6= P(E) and P( F^c)
0.7 = P( E or F) and P(E ^c or F ^c)
-1d-7 is the answer I'm pretty sure
Check the picture below.
keeping in mind that the point of tangency for a radius line and a tangent is alway a right-angle, since the "red" chord is parallel to the "green" tangent line outside, then the chord is cutting the "green" radius there in two equal halves at a right-angle, as you see in the picture.
we know the chord is 10 units long, so 5 + 5, since is perpendicularity with the radius will also cut the chord in two equal halves.
anyhow, all that said, we end up with triangle you see on the right-hand-side, and then we can just use the pythagorean theorem.