Question

Use synthetic division to evaluate (3x2 − 6x + 3) ÷ (x − 1). 3x − 9 3x2 − 3x 3x − 3 3x2 − 6

Answer 1

Answer:

$\frac{\left(3x^2-6x+3\right)}{\left(x-1\right)3x-93x^2-3x^3x-33x^2-6}: -\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}$
$\frac{3x^2-6x+3}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}$
$\frac{3\left(x-1\right)^2}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}$
$\frac{3\left(x-1\right)^2}{-3\left(x^4+41x^2+x+2\right)}$
$\frac{\left(x-1\right)^2}{-\left(x^4+41x^2+x+2\right)}$
$-\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}$