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3 years ago

On a map 1 cm = 50 mi. On the map, Grand Canyon is 4 cm from Phoenix. What is the actual distance?

Mathematics

1 answer:

Likurg_2 [28]3 years ago

4 0

Answer:

200

Step-by-step explanation:

1cm=50m

1*4=50*4

4=200 miles

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The width of a rectangle is 11.4 meters and its length is 18.7<br>Find the area.

vazorg [7]

Answer:

Area = 213.18

Step-by-step explanation:

11.4 x 18.7 = 213.18

Hope this helps you! :)

8 0

3 years ago

The percent decrease of an item that dropped in price from $50 to $43 is _____.

Stels [109]

Hopefully I’m correct but I think it is 7% because 50 -43 equals 7%

4 0

3 years ago

17.) Which of the following values is the least?<br>1-14), 114, 114, 721 196

grigory [225]

Answer:

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Step-by-step explanation:iwdyucbjcnwiuvbevjeyivbejkbchevbhe chksdb gbg svgfv e jcf dfv ve dc n dhcvgfefvgehncsjcbhdvdgvhj sn jshgvsjcvsgsdcvscjbsdguvsjcbs jbfjhgbhbcshbhvsgvdjjh jggvgcsjvjhfv

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3 years ago

Factor completely 81x2 − 100. (1 point) (10x − 9)(10x − 9) (10x − 9)(10x + 9) (9x − 10)(9x + 10) (9x − 10)(9x − 10)

MArishka [77]

The complete factorization of the equation 81x² - 100 is; (9x - 10)(9x + 10)

<h3>How to factorize quadratic equations?</h3>

We are given the quadratic equation;

81x² - 100

Now, according to quadratic identities, we know that;

(a + b) * (a - b) = a² - b²

Now, our equation can also be expressed as;

81x² - 100 = 9²x² - 10²

Thus, applying the quadratic identity gives us;

(9x + 10)(9x - 10)

Read more about factorization of quadratic equations at; brainly.com/question/1214333

#SPJ1

5 0

2 years ago

Integrate e^x(sin(x) cos(x))

Karo-lina-s [1.5K]

$I=\int e^x(\sin(x)\cos(x))dx=\int e^x(\frac{1}{2}\sin(2x))dx=\frac{1}{2}\int e^x\sin(2x)dx$

$\text{If }u=\sin(2x)\to du=2\cos(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
\text{Using }\int u\,dv=uv-\int v\,du:\\\\
I=\frac{1}{2}(e^x\sin(2x)-\int e^x(2\cos(2x))dx)\\\\
2I=e^x\sin(2x)-2\underbrace{\int e^x\cos(2x)dx}_{I_2}$

Looking for $I_2$ :

$\text{If}~u=\cos(2x)\to du=-2\sin(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\
I_2=e^x\cos(2x)-\int e^x(-2\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(2\sin(x)\cos(x))dx\\\\ I_2=e^x\cos(2x)+4\int e^x(\sin(x)\cos(x))dx=e^x\cos(2x)+4I$

Replacing:

$2I=e^x\sin(2x)-2I_2\iff\\\\2I=e^x\sin(2x)-2(e^x\cos(2x)+4I)\iff\\\\
2I=e^x\sin(2x)-2e^x\cos(2x)-8I\iff\\\\
10I=e^x\sin(2x)-2e^x\cos(2x)\iff\\\\
I=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))\\\\
\boxed{\int e^x(\sin(x)\cos(x))dx=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))+C}$

6 0

3 years ago