Answer:
358
Step-by-step explanation:
It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).
So, First we will do the sum of the three given polynomials,
Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)
=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)
=4a+8c
Now, we can perform the subtraction,
∴ Required difference
=(4a+8c)−(2a−3b+4c)
=4a+8c−2a+3b−4c
=2a+3b+4c
4 I THINK is the answer not 100% sure though
Answer:
The cost of the pillar is $22,947.12
Step-by-step explanation:
Diameter of the pillar = 6m
Radius = diameter / 2 = 6 / 2 = 3m
Height if the pillar = 7m
Volume of the pillar = πr²h
π = 3.14
V = 3.14 × 3² × 7
V = 3.14 × 9 × 7
V = 197.82m³
Volume of the pillar is 197.82m³
If 1m³ = $116
197.82m³ will cost $x
X = (197.82 × 116) / 1
X = $22,947.12
The cost of the pillar is $22,947.12
