Answer:
cos3x+tan3x=0
⟹cos3x=−tan3x
⟹cos3x=−sin3xcos3x
⟹cos23x=−sin3x
⟹1−sin23x=−sin3x
⟹sin23x−sin3x−1=0
This is a quadratic equation in sin3x.
sin3x=−(−1)±(−1)2−4×1×(−1)−−−−−−−−−−−−−−−−−√2×1
sin3x=1±5–√2
If x takes real values, the upper sign must be rejected.
sin3x=1−5–√2
⟹3x=nπ+(−1)nsin−11−5–√2
⟹x=13[nπ+(−1)nsin−11−5–√2]
Step-by-step explanation:
Hope this kind of helps
Answer:
Step-by-step explanation:
Slope of a line passing through two points
and
is given by the formula,
Slope = 
Slope of the line PQ passing through the two points P(-8, 2) and Q(4, 2) will be,
Slope '
' =
= 0
Therefore, slope of the line PQ parallel to the x-axis = 0
Slope of the line MN passing through the points M(8, 6) and N(8, -8) is,
Slope '
' =
= ∞
Therefore, slope of the line MN parallel to y-axis is undefined.
Since, angle between the x-axis and y-axis is 90°,angle at the intersection point between the lines parallel to x and y axis will be 90°.
These lines are perpendicular to each other.
Answer:
<h3>Option C. 6 : 1 is the answer.. </h3>
<h2>Hope it can help you and please mark me as a brainlist..</h2>
The answer would be 40% :)
The answer is the first one