I think it moves 5 units to the right Im not sure tho!!
It’s either B or D. I’m sorry I’m not so sure but I think it’s either one of those.
The denominator of a fraction can't be equal to 0.
The function is undefined at x=-1, x=2, x=4, because for these values the denominator of the function would equal 0, and it's impossible to divide by 0.
Edward is correct.
Answer:
<h2>
f⁻¹(x) = ∛(x+1)</h2>
Step-by-step explanation:
Given the encoded message defined by the function f(x) = x³-1, the inverse function that the decoder would need when the message is received can be expressed as thus:
let the inverse of the function be represented as y such that y = x³-1.
Making x the subject of the formula from the equation above;
x³ = y+1
Taking the cube root of both sides:
∛x³ = ∛(y+1)
x = ∛(y+1)
replacing y with x:
y = ∛(x+1)
f⁻¹(x) = ∛(x+1)
The encoded message is the inverse function ∛(x+1)
Answer:
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Step-by-step explanation:
