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2 years ago

Is this question correct?

Mathematics

1 answer:

Andrews [41]2 years ago

6 0

Answer:

10^20

3^11

3^24

10^12

Step-by-step explanation:

(10^2)^10=10^2*10=10^20

3^3*3^8=3^3+8=3^11

(3^3)^8=3^3*8=3^24

10^2*10^10=10^2+10=10^12

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2/7 times 2/6 = what

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2 years ago

Which of the following sets are continuous? Please help

Alecsey [184]

Answer:

A, C and D are continuous

Step-by-step explanation:

A is a set of any number x which 30 < x <=45

B is a set that contains only 3 and 7

C is a set of any number x which 60 <= x < 100

D is a set of any number x which -infinity < x < + infinity

E is a set that contains only even whole numbers

A continuous data set is a quantitative data set representing a scale of measurement that can consist of numbers other than whole number, like decimals and fractions.

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3 years ago

21 is 84 percent of what number

marysya [2.9K]

Let the required no. be x then according to question
(84/100)*x = 21
x = 21*(100/84)
x = 2100/84
x = 25

hence the required no. is 25

hope it helped

5 0

3 years ago

Ada, Betty, Chris and David have $45 in total Ada gota 52 fromBetty, Chris tripleshis money and Davids money is cut by hall four

andrezito [222]

Using a system of equations, it is found that initially Ada has $0.385.

For the system, we have that the variables are:

x is Ada's amount.
y is Betty's amount.
z is Chris's amount.
w is David's amount.

$45 total, hence:

$x + y + z + w = 45$

Ada gets 2 from Betty, hence:

$x + 2 = y - 2$

$x = y - 4$

$y = x + 4$

Chris triples his money and David's money is cut by half four of them have the same amount, hence:

$x + 4 = y = 3z = \frac{w}{2}$

Then:

$3z = x + 4$

$z = \frac{x + 4}{3}$

$x + 4 = \frac{w}{2}$

$w = 2x + 8$

Solving for w, we find Ada's initial amount.

$x + y + z + w = 45$

$x + x + 4 + \frac{x + 4}{3} + 2x + 8 = 45$

$4x + 12 + \frac{x + 4}{3} = 45$

$12x + 36 + x + 4 = 45$

$13x = 5$

$x = \frac{5}{13}$

$x = 0.385$

Initially, Ada has $0.385.

A similar problem is given at brainly.com/question/6120515

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2 years ago