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alexandr1967 [171]
3 years ago
12

The annual health care costs for two new companies that opened in the year 2000 are shown on the graphs below.

Mathematics
2 answers:
Mama L [17]3 years ago
7 0
<span>Company 1:
Average yearly increases in health care costs for the Company 1 over the first 12 years is:
r1=[f(12)-f(0)]/(12-0)
r1=[f(12)-f(0)]/12

f(12)=(24,000+36,000)/2
f(12)=60,000/2
f(12)=30,000

f(0)=12,000

r1=(30,000-12,000)/12
r1=18,000/12
r1=1,500

</span>Company 2:
Average yearly increases in health care costs for the Company 2 over the first 12 years is:
r2=[g(12)-g(0)]/(12-0)
r2=[g(12)-g(0)]/12

g(12)=(36,000+48,000)/2
g(12)=84,000/2
g(12)=42,000

g(0)=[12,000+(12,000+24,000)/2]/2
g(0)=(12,000+36,000/2)/2
g(0)=(12,000+18,000)/2
g(0)=30,000/2
g(0)=15,000

r2=(42,000-15,000)/12
r2=27,000/12
r2=2,250<span>

r2=2,250>1,500=r1
r2-r1=2,250-1500
r2-r1=750

Answer: Fourth option:
</span><span>Over the first 12 years, the average yearly increase in health care costs for company 2 is greater than the average yearly increase in health care costs for company 1 by about $750.</span>
velikii [3]3 years ago
3 0

Answer:

Answer: Fourth option:

Over the first 12 years, the average yearly increase in health care costs for company 2 is greater than the average yearly increase in health care costs for company 1 by about $750.

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136/50<br> as a percentage?
aleksandrvk [35]

Answer: 272%

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136/50 * 100 = 2.72 * 100 = 272%

And finally we have:

136/50 as a percent equals 272%

4 0
3 years ago
Read 2 more answers
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