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sergiy2304 [10]
3 years ago
6

A bag contains a mixture of 300 red and 75 yellow candies. If you choose one candy at random, what is the probability that it is

yellow?
Mathematics
1 answer:
natta225 [31]3 years ago
4 0

Answer: A solid 4% chance of picking a yellow

brainliest plz

Step-by-step explanation: We first should combine 300 and 75 because those are the total values of the candies in the bag. After, we should divide the different candies by the total amount of them getting the numbers .8 for red and .2 for yellow. Since the question is that the yellow occurs but not the red and you can miss the bag you would want to calculate what the probability would be to have B happen but not A. The equation for that is:

(1 - P(A)) × P(B)  

where P(A)=.8 and P(B)=.2

plugging in all things it would be

(1-.8)*.2

which equals .04 or 4%

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The first table has x-values of -1, 3, and 6, and y-values of 4, 5, and 6. This means that the domain and range would be given by the following sets:
Domain: {-1, 3, 6}
Range: {4, 5, 6}

The second set of points has x-values of -4, -4, -3, and 1, and y-values of 1, 1, 3, and 4. Duplicate points are not listed within the domain and range, so the domain and range would be given by the following sets:
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2 years ago
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Tell whether you can make a unique triangle or no triangle with these conditions: angles measuring 45° and 90°
just olya [345]

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A number added to 8 times that numbers reciprical is 6, find the number
castortr0y [4]
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3 years ago
Find the minimum value of the function f(x)=x^2+5x-6
mash [69]
<h3><u>Explanation</u></h3>
  • Method 1 (Formula)

\begin{cases}h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{2a}  \end{cases}

The vertex of Parabola is the maximum/minimum point depending on the value of a.

  • Find Vertex

<u>h-value</u>

h =  -  \frac{5}{2(1)}  \\ h =  -  \frac{5}{2}

<u>k-value</u>

k =  \frac{4(1)( - 6) -  {(5)}^{2} }{4(1)}  \\ k =  \frac{ - 24 - 25}{4}  \\ k =  \frac{ - 49}{4}  \\ k =  -  \frac{49}{4}

The minimum value is the value of k. Therefore the minimum value is - 49/4 at x = -5/2.

  • Method 2 (Derivative)

This is Calculus method. We simply differentiate the function then substitute y' = 0.

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f'(x) = 2 {x}^{2 - 1}  +  {5x}^{1 - 1}  - 0 \\ f'(x) = 2x + 5

Substitute f'(x) = 0

0 = 2x + 5 \\  - 5 = 2x \\   -  \frac{5}{2}  = x

Substitute x = -5/2 in the original equation.

f(x) =  {( -  \frac{5}{2} )}^{2}  + 5( -   \frac{5}{2} ) - 6 \\ f(x) =  \frac{25}{4}  -  \frac{25}{2}  - 6 \\ f(x) =  \frac{25}{4}  -  \frac{50}{4}  -  \frac{24}{4}  \\ f(x) =  \frac{25}{4}  -  \frac{74}{4}  \\ f(x) = -   \frac{49}{4}

<h3><u>Answer</u><u /></h3>

<u>\sf{the  \:  \: minimum  \:  \: value \:  \:  is   \:  \: -  \frac{49}{4}  \:  \: at \:  \:  x =  -  \frac{5}{2} }</u>

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