Nick spent 2/3 of his money on games, the rest was spent on lunch. If lunch cost $10 how much money did he have at first?

Evan is making a table that will be created in the shape of the figure below. The table top is a triangle attached to a rectangl

Yakvenalex [24]

Given:
Triangle:
height = 6ft
base = 4ft

Rectangle:
length = x
Width = 6 ft

Surface Area = 150ft²

Area of a Triangle = h*b / 2 = (6ft * 4ft) / 2 = 12ft²

Area of a rectangle = Surface Area - Area of a Triangle
A = 150 ft² - 12 ft² = 138 ft²

138 ft² = x * 6ft
138 ft² / 6 ft = x
23 ft = x.

6 0

3 years ago

What is your sister’s total cost under each of the two plans?2. Suppose your sister doubles her monthly usage to 3,500 minutes a

chubhunter [2.5K]

Answer:

(1) The total cost under Plan A is $92 and the total cost under Plan B is $515.

(2) The total cost under Plan A is $92 and the total cost under Plan B is $1,030.

Step-by-step explanation:

The question is incomplete, so the complete question is below:

$A\ cell \ phone \ company\ offers\ two \ different \ plans.$

$Plan\ A\ costs\ \$92\ per\ month\ for\ unlimited\ talk\ and\ text.\ Plan\ B\ costs \ $0.20\ per\ minute\ plus\ \$0.10\ per\ text\ message\ sent.$ $You\ need \ to\ purchase \ a \ plan \ for\ your \ 14-year-old \ sister$ $.Your\ sister\ currently \ uses\ 1,750 \ minutes\ and \ sends\ 1,650 \ texts\ each \ month.$ $(1) What\ is\ your \ sister's\ total\ cost\ under \ each\ of\ the\ two\ plans?$

$(2) Suppose\ your\ sister\ doubles\ her\ monthly\ usage \ to\ 3,500\ minutes \ and\ sends\ 3,300 \ texts.$ $What \ is \ your \ sister's \ total \ cost \ under \ each \ of \ the \ two \ plans?$

Now, to find (1) total cost for each of the two plans. (2) Total cost under each of the two plans, if sister doubles her monthly usage to 3,500 minutes and sends 3,300 texts.

As, the Plan A is for unlimited talk and text

Cost of the Plan A = $92.

Now, to find the cost under Plan B:

According to question:

Rate of call per minute is $0.20 and per text is $0.10.

Calls she uses currently is 1,750 minutes and text 1,650.

So, to get the cost of Plan B:

$0.20\times 1750+0.10\times 1650$

$=350+165$

$=515.$

Thus, Plan B costs $515.

Now, to get the total cost as, sister doubles her monthly usage to 3,500 minutes and sends 3,300 texts.

As, the Plan A is same in both cases and is for unlimited text and calls.

So, cost of Plan A = $92.

As, the monthly usage is double.

Calls in minutes are 3,500.

Texts are 3,300.

Now, to get the total cost under Plan B:

$0.20\times 3500+0.10\times 3300$

$=700+330$

$=1030.$

Hence, the cost of Plan B = $1,030.

Therefore, (1) The total cost under Plan A is $92 and the total cost under Plan B is $515.

(2) The total cost under Plan A is $92 and the total cost under Plan B is $1,030.

7 0

3 years ago

A computer supplies store is having a store wide sale this weekend. And inkjet printer that normally sells for $179 is on sale f

klasskru [66]

Hey again!

i don't know if i am doing this correctly but i will give it a go

179 - 143.20 = 35.8

179 / 35.8 = 5

so this would mean from 179 to 143.20 their is a 5% discount

Hope This Helps!

8 0

3 years ago

For the problem, use the discriminant to determine the number of real solutions for the equation. Then, find the solutions and c

Ksivusya [100]

Answer:

Discriminant = 55.2 > 0 -> 2 real solutions

Solutions: t1 = -1.1663 s and t2 = 0.35 s

The solution t1 doesn't make sense for this problem, as we can't have a negative value for the time.

So the solution is t2 = 0.35 s

Step-by-step explanation:

To find the time when the ball will reach the height of 2 meters, we just need to use the value of h = 2 in the equation given. So, we have that:

−4.9t^2 − 4t + 4 = 2

−4.9t^2 − 4t + 2 = 0

For this equation, we have the constants a = -4.9, b = -4 and c = 2. So the discriminant Delta is:

Delta = b^2 - 4ac = 16 + 39.2 = 55.2

sqrt(Delta) = 7.4297

As Delta > 0, we have 2 real solutions

t1 = (-b + sqrt(Delta)) / 2a = (4 + 7.4297) / (-9.8) = -1.1663 s

t2 = (-b - sqrt(Delta)) / 2a = (4 - 7.4297) / (-9.8) = 0.35 s

Number of real solutions: 2

Solutions: t1 = -1.1663 s and t2 = 0.35 s

The solution t1 doesn't make sense for this problem, as we can't have a negative value for the time.

So the solution is t2 = 0.35 s

8 0

3 years ago

In a certain clothing store, 3 shirts and 5 ties cost $60, and 2 shirts and 3 ties cost $39. What is the cost of each shirt?

Dovator [93]

Let shirts be x and ties be y
3x+5y=$60 Equation 1 (Equation 1 will be denoted by *)
2x+3y=$39 Equation 2 (Equation 2 will be denoted by !)
*x2 6x + 10y = $120
!x3 6x + 9y = $117
*-! y = 120-117 =3

Ties are $3 each
Substitute this value back into one of the original 2 equations:
3x+5y=$60
3x+(5x3) = 60
3x+15=60
3x=45
x=15

Shirts are $15

6 0

3 years ago

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