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Sloan [31]
3 years ago
7

-4(8h-5)= -16 round to the nearnest hundreth

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

h=9/8 or 1.125 but since yo said round it's 1.13

Step-by-step explanation:

You might be interested in
An electronics hobbyist has three electronic parts cabinets with two drawers each.
Andrews [41]

Answer:

a) 0.5 = 50% probability that an NPN transistor will be selected.

b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types

c) 66.67% probability that it comes from the cabinet that contains only NPN transistors

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

a) What is the probability that an NPN transistor will be selected?

1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.

So

p = \frac{1}{3}*1 + \frac{1}{3}*0 + \frac{1}{3}*0.5 = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = 0.5

0.5 = 50% probability that an NPN transistor will be selected.

b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?

Here we use the conditional probability formula.

Event A: NPN transistor

Event B: From the third cabinet.

50% probability that an NPN transistor will be selected, so P(A) = 0.5.

1/6 probability that it is from the third cabinet and NPN, so P(A \cap B) = \frac{1}{6}

The desired probability is:

P(B|A) = \frac{\frac{1}{6}}{0.5} = 0.3333

0.3333 = 33.33% probability that it came from the cabinet that contains both types.

c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?

Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So

x + 33.33 = 100

x = 66.67

66.67% probability that it comes from the cabinet that contains only NPN transistors

6 0
3 years ago
Tori worked 48 hours one week. Her hourly pay for 40 hours is $16.20. Her overtime rate is 1.5. What was her
konstantin123 [22]
Her total pay that week was $660
5 0
2 years ago
??????????????????????
I am Lyosha [343]
The answer is A. Closure
6 0
2 years ago
Two competing gyms each offer childcare while parents work out. Gym A charges $9.00 per hour of childcare. Gym B charges $0.75 p
Aleks [24]

Answer:

11000 JY.

Step-by-step explanation:

According to today's exchange rate

1 US dollar = 110 JY

100 US dollars = 100 * 110 JY

You should get 11000 JY.

Pick the answer that is closest to this exchange rate.

8 0
2 years ago
Han spent 75 minutes practicing the piano over the weekend. For each question, explain or show your reasoning. A. Priya practice
irakobra [83]

Answer:

a. 114 minutes

b. 48 minutes

Step-by-step explanation:

Given that

Time spent over the piano is 75 minutes

a. if Priya practice violin for 152% as Han Practiced for piano

So the minutes she practice in Violin is

= 75 minutes × 152%

= 114 minutes

Likewise

b. If Tyler practiced for clarinet for 64% as Han Practiced for piano

So the minutes he practice in Clarinet is

= 75 minutes × 64%

= 48 minutes

The same is to be considered

4 0
2 years ago
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