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ELEN [110]
3 years ago
8

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Mathematics
1 answer:
frozen [14]3 years ago
7 0

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

(x,y)\to (y,-x)

Using this rule, we get

A(-3,6)\to A'(6,3)

B(2,9)\to B'(9,-2)

C(1,1)\to C'(1,-1)

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

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Answer:

y = 1/2x + 3

O f(x)= 1/2x+3

Step-by-step explanation:

f(x) = 2x - 6

y = 2x - 6

x = 2y - 6

2y = x + 6

y = (x + 6)/2

y = 1/2x + 3

4 0
3 years ago
Please help me I have to turn in by 8:00
Diano4ka-milaya [45]

Answer:

A 2

Step-by-step explanation:

When we divide x by 9 there is some whole number we will call y plus a remainder of 4

x/9 = y  remainder 4

Writing this in fraction form

x/9 = y + 4/9

Multiplying each side by 9

9*x/9 = 9* y + 4/9 *9

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Multiply each side by 2

2x = 2*(9y+4)

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Add 3 to each side

2x+3 = 18y +8+3

2x+3 = 18y +11

Divide each side by 9

(2x+3)/9 = 18y/9 +11/9

              = 2y + 9/9 +2/9

               =(2y+1 + 2/9)

  We know y is a whole number and 1 is a whole number so we can ignore 2y +1 when looking for a remainder)

2/9 is a fraction

Taking this back from fraction form to remainder from

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7 0
2 years ago
K+ 6 ≥ 19, if k = 11
WINSTONCH [101]

Answer:

Then it would be the other way around 19 ≥ k + 6

Wait for more responses if needed.

4 0
2 years ago
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Which of the following numbers is not a perfect square?<br><br> 24<br> 25<br> 64<br> 100
stich3 [128]
Hi! 

A perfect square is the product of when a whole number is multiplied by itself

Ex:

6 × 6 = 36, 36 is the perfect square. 

The number that is being multiplied is the square root. 

So to find the correct answer for this question, let's use the process of elimination. 

100 = 10 × 10 so we can cross out 100

64 = 8 × 8 so we can cross out 64

25 = 5 × 5 so we can cross out 25

Now all we have left is 24, which is not a perfect square. 

Answer: A. 24

Hope this helps :)
8 0
3 years ago
Read 2 more answers
PLEASE HELP FOR TEST will mark brainiest !!
sdas [7]

Answer:

552.920307 yd^2 or 552.92 yd^2 for sigfigs

Step-by-step explanation:

basically you take the area of the entire circle and subtract the interior circle to leave the ring and that’s your answer

so the area formula of a circle is π r^2

the radius (r) is just half the diameter so the entire diameter is 48 so the radius is 24 - π(24)^2 = 1809.557368^2

then the interior circle’s diameter is 40 so the radius is 20 - π(20)^2 = 1256.637061^2

so now it’s just subtraction:

1809.557368 yd^2 - 1256.637061 yd^2 =
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hope this helps :)

6 0
2 years ago
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