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4 years ago

NEED HELP ASAP WITHIN 10 MINUETS MY ASSIGNMENT IS DO PLEASE HELP!

2 answers:

5 0

Answer: I do not have expertise on this so I won't answer the exact problem but this sounds like exponential decay, where you have the decay rate. I know that the formula for exponential decay is: y = a(1 - r)^x

I'm sorry if this does not help much I don't have expertise on this. Sorry again.

Step-by-step explanation:

horrorfan [7]4 years ago

4 0

Answer:

156.25 grams

Step-by-step explanation:

Well, for starters we know that the substance decays by 2% each day and its been decaying for 34 days. Therefore, the substance has decayed by 68%

34 x 2 = 68

Hence, 50 grams is 32% because the substance has already decayed by 68%

100 - 68 = 32

So now we know 50 grams is 32%. Now we need to find how much 100% is.

50 - 32%

X - 100%

We cross multiply.

50 x 100 = 5000

And divide.

5000 / 32 = 156.25

Thus, in the beginning, there were 156.25 grams in the substance.

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HELPP!!! Ali is competing in a 10-meter high diving event. When he dives, he reachers a maximum height of 12 meters and travels

Andrew [12]

Answer: 56

Step-by-step explanation:

1. 10+12=22

2. 22+3.4= 56

+34

5 6

56 is your anwser

7 0

4 years ago

PLEASE HELP

Svetach [21]

Answer:

Use the calculator.

Step-by-step explanation:

Do u use insta

8 0

3 years ago

A triangular pyramid is formed from three right triangles as shown below.

Bess [88]

Answer:

FH = 108

Step-by-step explanation:

The given figure requires we use the Pythagorean theorem to write two relations involving right triangle side lengths. The Pythagorean theorem tells us the square of the hypotenuse is the sum of the squares of the other two sides.

<h3>Triangle EGH:</h3>

EG² = GH² +HE²

GH² = EG² -HE² = 53² -28² = 2025 . . . . . solve for GH², use given values

<h3>Triangle FGH:</h3>

FG² = GH² +FH²

FH² = FG² -GH² = 117² -2025 = 11664 . . . . solve for FH², use known values

FH = √11664 = 108 . . . . . take the square root

The length FH is 108.

6 0

3 years ago

Brainliest will be given to the correct answer!

IrinaK [193]

Answer:

A) The height of the trapezoid is 6.5 centimeters.

B) We used an algebraic approach to to solve the formula for $b_{1}$ . $b_{1} = \frac{2\cdot A}{h}-b_{2}$

C) The length of the other base of the trapezoid is 20 centimeters.

D) We can find their lengths as both have the same length and number of variable is reduced to one, from $b_{1}$ and $b_{2}$ to $b$ . $b = \frac{A}{h}$

Step-by-step explanation:

A) The formula for the area of a trapezoid is:

$A = \frac{1}{2}\cdot h \cdot (b_{1}+b_{2})$ (Eq. 1)

Where:

$h$ - Height of the trapezoid, measured in centimeters.

$b_{1}$ , $b_{2}$ - Lengths fo the bases, measured in centimeters.

$A$ - Area of the trapezoid, measured in square centimeters.

We proceed to clear the height of the trapezoid:

1) $A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})$ Given.

2) $A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})$ Definition of division.

3) $2\cdot A\cdot (b_{1}+b_{2})^{-1} = (2\cdot 2^{-1})\cdot h\cdot [(b_{1}+b_{2})\cdot (b_{1}+b_{2})^{-1}]$ Compatibility with multiplication/Commutative and associative properties.

4) $h = \frac{2\cdot A}{b_{1}+b_{2}}$ Existence of multiplicative inverse/Modulative property/Definition of division/Result

If we know that $A = 91\,cm^{2}$ , $b_{1} = 16\,cm$ and $b_{2} = 12\,cm$ , then height of the trapezoid is:

$h = \frac{2\cdot (91\,cm^{2})}{16\,cm+12\,cm}$

$h = 6.5\,cm$

The height of the trapezoid is 6.5 centimeters.

B) We should follow this procedure to solve the formula for $b_{1}$ :

1) $A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})$ Given.

2) $A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})$ Definition of division.

3) $2\cdot A \cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot (b_{1}+b_{2})$ Compatibility with multiplication/Commutative and associative properties.

4) $2\cdot A \cdot h^{-1} = b_{1}+b_{2}$ Existence of multiplicative inverse/Modulative property

5) $\frac{2\cdot A}{h} +(-b_{2}) = [b_{2}+(-b_{2})] +b_{1}$ Definition of division/Compatibility with addition/Commutative and associative properties

6) $b_{1} = \frac{2\cdot A}{h}-b_{2}$ Existence of additive inverse/Definition of subtraction/Modulative property/Result.

We used an algebraic approach to to solve the formula for $b_{1}$ .

C) We can use the result found in B) to determine the length of the remaining base of the trapezoid: ( $A= 215\,cm^{2}$ , $h = 8.6\,cm$ and $b_{2} = 30\,cm$ )

$b_{1} = \frac{2\cdot (215\,cm^{2})}{8.6\,cm} - 30\,cm$

$b_{1} = 20\,cm$

The length of the other base of the trapezoid is 20 centimeters.

D) Yes, we can find their lengths as both have the same length and number of variable is reduced to one, from $b_{1}$ and $b_{2}$ to $b$ . Now we present the procedure to clear $b$ below:

1) $A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})$ Given.

2) $b_{1} = b_{2}$ Given.