The horizontal distance between the two balloons is 53.8 meters.
<u><em>Explanation</em></u>
According to the below diagram, A and B are the positions of two balloons which are 48.2 meter and 61.0 meter above the ground respectively.
Horizontal distance between two balloons is AC, which is
meter.
A person in the left balloon observes that the right balloon is 13.38° above the horizontal. That means, ∠BAC = 13.38°
According to the diagram, 
Now in right angle triangle ABC.....

So, the horizontal distance between the two balloons is 53.8 meters.
2. TU, UV and TV are mid-segments
3. Definition of mid-segment
4. Division property of equality
6. SSS similarity theorem
Solution:
Step 1: Given
T is the midpoint of QR.
U is the midpoint of QS.
V is the midpoint of RS.
Step 2: Mid-segments connects midpoints of opposite sides.
TU, UV and TV are mid-segments.
Step 3: By definition of mid-segment
A triangle mid-segment is parallel to the third side of the triangle and is half of the length of the third side.
and 
Step 4: By division property of equality
Divide first segment by RS, second segment by QR and third segment by SQ.

Step 5: By transitive property

Step 6: From the above steps, the sides of the triangle are congruent.
By SSS similarity theorem,

Hence proved.
Answer: If you want you can put 480 seconds or 8 minutes.
480 seconds = 8 minutes
Step-by-step explanation:
8 inches multiply by 60 feet
A. The scale used to make the model was 125 meters =1 foot. 525 divided by 4.2 equals 125 meters.
B. The model is 84 sheets of plywood tall.
4.2 feet = 50.4 meters 50.4 meters divided by 0.6 equals 84 sheets.