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kkurt [141]
3 years ago
12

(997)2 + 6 x 997 + 9​

Mathematics
1 answer:
Igoryamba3 years ago
5 0

Answer: 1,000,000

Step-by-step explanation:

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

997 times its self

994,009+6x997+9

994,009+5,982+9

994,009+5,982= 999,991

999,991+9= 1,000,000

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Answer:

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Step-by-step explanation:

I came to this answer with simple deduction and process of elimination.

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100) Reflect the point in (a) the x-axis and (b) the y-axis.
klemol [59]

Answer:

Step-by-step explanation:

36. (4,1)

x-axis(4,-1)

y-axis(-4,1)

37.(-2,3)

x-axis(2,-3)

y-axis(-2,3)

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x-axis(-2,5)

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4 0
3 years ago
Answer?........................
ad-work [718]

Answer:

x- intercept = - 1 , y- intercept = 2

Step-by-step explanation:

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the y- intercept is the value of the y- coordinate where the curve crosses the y- axis , that is

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4 0
2 years ago
Kamal and Anand each Lent the same sum of money for 2 years at 5 percent at simple interest and compound interest respectively.
Ivenika [448]

Answer:

  • amount lent: ₹6000
  • interest received: Kamal, ₹600; Anand, ₹615.

Step-by-step explanation:

For principal P invested at simple interest rate r, the returned value in t years is ...

  A = P(1 +rt)

If K is Kamal's returned value, the given numbers tell us ...

  K = P(1 +0.05·2) = 1.1P

__

For principal P invested at compound interest rate r, with interest compounded annually for t years, the returned value is ...

  A = P(1 +r)^t

If A is Anand's returned value, the given numbers tell us ...

  A = P(1.05)² = 1.1025P

This latter amount is RS.15 more than the former one, so we have ...

  1.1025P = 1.1P +15

  0.0025P = 15 . . . . . . . . subtract 1.1P

  P = 6000 . . . . . . . . . . . divide by 0.0025 . . . .  the amount lent

Kamal received 1.1P -P = 0.1P = 600 on the investment.

Each lent ₹6000. Kamal received ₹600 in interest; Anand received ₹615 in interest.

4 0
3 years ago
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