Consider
.. X = {1, 2, 3, 4}, x = 4
.. Y = {2, 3, 4, 5, 6}, y = 5, w = 3
The elements in X or Y (X ∪ Y) are {1, 2, 3, 4, 5, 6}, n = 6.
.. n = 6 = 4 + 5 - 3
Note that if we just add x and y, we count the common elements twice. In order to just count the common elements once, we need to subtract that count from the total of x and y.
selection B is appropriate.
Answer:
x
=
ln
(
3
)
7
ln
(
3
)
+
ln
(
7
)
Step-by-step explanation:
It's the last option again. You have 1 linear factor (3<em>x</em>) and 2 copies of a quadratic factor (<em>x</em>² + 10), and the partial fractions with the quadratic factor need to have a linear polynomial in the numerator.
Answer:
factor is the answer
Step-by-step explanation:
I took the test
Answer:
17
Step 1: rerrange the data
8 , 10, 12, 14, 17, 19, 19, 22, 24
Q2 is the median
see that the middle number is 17
