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3 years ago

10

What is the rational number equivalent to 1.28 repeating

1 answer:

AleksandrR [38]3 years ago

3 0

The answer is X=127/99

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How do I find the exact product of 379 & 8?

xxMikexx [17]

Product means the result you get after multiplying. So you have to multiply the two numbers. 379*8 = 3032

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4 years ago

I do not understand this

katrin [286]

Neither do i lol drop out of school

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3 years ago

Find the dimensions of a rectangle (in m) with area 1,000 m2 whose perimeter is as small as possible. (Enter the dimensions as a

Amanda [17]

The perimeter of the rectangle is the sum of its dimensions

The dimensions that minimize the perimeter are $\mathbf{10\sqrt{10 },10\sqrt{10 }}$

The area is given as:

$\mathbf{A = 1000}$

Let the dimension be x and y.

So, we have:

$\mathbf{A = xy = 1000}$

Make x the subject

$\mathbf{x = \frac{1000}{y}}$

The perimeter is calculated as:

$\mathbf{P = 2(x + y)}$

Substitute $\mathbf{x = \frac{1000}{y}}$

$\mathbf{P = 2(\frac{1000}{y} + y)}$

Expand

$\mathbf{P = \frac{2000}{y} + 2y}$

Differentiate

$\mathbf{P' = -\frac{2000}{y^2} + 2}$

Set to 0

$\mathbf{ -\frac{2000}{y^2} + 2 = 0}$

Rewrite as:

$\mathbf{ -\frac{2000}{y^2} = -2}$

Divide both sides by -1

$\mathbf{\frac{2000}{y^2} = 2}$

Multiply y^2

$\mathbf{2000 = 2y^2}$

Divide by 2

$\mathbf{1000 = y^2}$

Take square roots of both sides

$\mathbf{y = \sqrt{1000 }}$

$\mathbf{y = 10\sqrt{10 }}$

Substitute $\mathbf{y = \sqrt{1000 }}$ in $\mathbf{x = \frac{1000}{y}}$

$\mathbf{x = \frac{1000}{\sqrt{1000}}}$

$\mathbf{x = \sqrt{1000}}$

$\mathbf{x = 10\sqrt{10 }}$

Hence, the dimensions that minimize the perimeter are $\mathbf{10\sqrt{10 },10\sqrt{10 }}$

Read more about perimeters at:

brainly.com/question/6465134

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3 years ago

PLS HELP ME ASAP FOR QUESTION 11 AND 13!! (MUST SHOW WORK!!) + LOTS OF POINTS!! *brainliest*

sergejj [24]

Yeah you are my favorite person to do that you are welcome and you can come

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4 years ago

Differentiating Exponential functions In Exercise,find the derivative of the function. See Example 2 and 3.

Citrus2011 [14]

Answer:

$f'(x)=-5ae^{ax}=a f(x)$ , where a be a constant.

Step-by-step explanation:

Note: The given functions is a constant function because variable term is missing.

Consider the given function is

$f(x)=-5e^{ax}$

where a be a constant.

We need to find the derivative of the function.

Differentiate with respect to x.

$f'(x)=\dfrac{d}{dx}(-5e^{ax})$

$f'(x)=-5\dfrac{d}{dx}(e^{ax})$

$f'(x)=-5e^{ax}\dfrac{d}{dx}(ax)$ $[\because \dfrac{d}{dx}(e^x)=e^x]$

$f'(x)=-5ae^{ax}$

$f'(x)=a(-5e^{ax})$

$f'(x)=a f(x)$

Therefore, the derivative of the function is $f'(x)=-5ae^{ax}=a f(x)$ .

7 0

3 years ago