<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
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<span>Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
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Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
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</span><span>Answer: correct choice is B.
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Answer:
arc PQ = 124°
Step-by-step explanation:
The inscribed angle PRQ is half the measure of its intercepted arc PQ, so
arc PQ = 2 × 62° = 124°
Initial equation:
4a / 2 = 5.2
Multiply both sides by 2:
4a = 10.4
Divide both sides by 4:
a = 2.6
Hope this helps!! :)
Answer:
P+6=B
Where 'B' is the total number of batteries purchased
