Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
Answer:
G. 
Step-by-step explanation:
Given that figure I and figure II are similar, it follows that the ratio of their corresponding side lengths are equal and the same.
Thus:
Therefore, the proportion that must be true is:
✔️
Answer:
Step-by-step explanation:
Fuji Apples: 7/6 = <u>$1.16</u>
Golden Delicious Apples: 1/0.75 = 100/75 = $<u>1.33</u>
Macintosh Apples: <u>$2</u>
Hope this helps! :3
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Answer:
what is x
Step-by-step explanation:
way to solve for this is to set up the base and height. then you can use the area (if given) to divide the area from the side you know to get your answer.
Answer:
(x-6)(x+2)
Step-by-step explanation:
Use FOIL to check if the factors work.
x * x = x²
(x * 2) + (x * -6) = 2x - 6x = -4x
-6 * 2 = -12
